Data Structures and Algorithms in Java
Data Structures and Algorithms in Java
6th Edition
ISBN: 9781119278023
Author: Michael T. Goodrich; Roberto Tamassia; Michael H. Goldwasser
Publisher: Wiley Global Education US
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Chapter 3, Problem 26C

Explanation of Solution

Algorithm to concatenate two doubly linked list:

The algorithm to concatenate two doubly linked list “L” and “M” into single list “L'” is given below:

Algorithm:

Input: Two doubly linked list “L” and “M”.

Output: Concatenate the two doubly linked lists into single list “L'”.

Concatenate(L, M):

  //Create new nodes

  Create a new node "n" and "v"

/*Get previous node for trailer of list "L" using getPrev() method and assign into "n". */

  n = (L.getTrailer()).getPrev()

/*Get next node for header of list "M" using getNext() method and assign into "v" */

  v = (M.getHeader()).getNext()

// Set next node for header of list "M" as "null"

  (M.getHeader()).setNext(null)

//Set previous node for trailer of list "L" as "null"

  (L.getTrailer()).setPrev(null)

/*Call setNext() method by passing the "v" node to set the next node as "v". */

  n.setNext(v)

/*Call setPrev() method by passing the "n" node to set the previous node as "n". */

  v.setPrev(n)

  //Assign the concatenated list into single list "L'"

  L' = L

/*Set trailer for list "L'" by calling setTrailer() method by passing parameter as "trailer of list "M"...

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1. Unsigned Integers If we have an n-digit unsigned numeral dn-1d n-2...do in radix (or base) r, then the value of that numeral is n−1 r² di Σi=0 which is basically saying that instead of a 10's or 100's place we have an r's or r²'s place. For binary, decimal, and hex r equals 2, 10, and 16, respectively. Just a reminder that in order to write down a large number, we typically use the IEC or SI prefixing system: IEC: Ki = 210, Mi = 220, Gi = 230, Ti = 240, Pi = 250, Ei = 260, Zi = 270, Yi = 280; SI: K=103, M = 106, G = 109, T = 10¹², P = 1015, E = 10¹8, Z = 1021, Y = 1024. 1.1 Conversions a. (15 pts) Write the following using IEC prefixes: 213, 223, 251, 272, 226, 244 21323 Ki8 Ki 223 23 Mi 8 Mi b. (15 pts) Write the following using SI prefixes: 107, 10¹7, 10¹¹, 1022, 1026, 1015 107 10¹ M = 10 M = 1017102 P = 100 P c. (10 pts) Write the following with powers of 10: 7 K, 100 E, 21 G 7 K = 7*10³
answer shoul avoid using AI and should be basic and please explain
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