Explanation Given data: Refer to Figure 3.66 in the textbook for the nodal analysis. In the given circuit, i o is the current flow through 4 Ω resistor. Calculation: Modify the given figure with the representation of node voltages and current directions as shown in Figure 1. Apply Kirchhoff’s current law at node v 1 in Figure 1. 60 − v 1 4 − v 1 − v 2 2 − v 1 − 0 8 = 0 60 4 − v 1 4 − v 1 2 + v 2 2 − v 1 8 = 0 ( − 1 4 − 1 2 − 1 8 ) v 1 + v 2 2 = − 60 4 − 0.875 v 1 + 0.5 v 2 = − 15 (1) Apply Kirchhoff’s current law at node v 2 in Figure 1. 60 − v 2 10 + v 1 − v 2 2 + 3 i o = 0 60 10 − v 2 10 + v 1 2 − v 2 2 + 3 i o = 0 v 1 2 − v 2 ( 1 2 + 1 10 ) + 3 i o = − 60 10 0.5 v 1 − 0.6 v 2 + 3 i o = − 6 (2) With reference to Figure 1, write the expression for the current i 0 flows through 4 Ω resistor. i o = ( 60 V ) − v 1 4 Ω (3) Substitute equation (3) in (2)

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ISBN: 8220102801448

Author: Alexander

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Chapter 3, Problem 17P

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Find the current i o in the circuit of Figure 3.66.

Solution Summary: The author explains how to find the value of current i_o in the circuit of Figure 3.66.

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Find the current io in the circuit of Figure 3.66.

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