Chapter 3, Problem 16CP

(a)

Explanation of Solution

Given: The following code:

if (number % 2 == 0)

cout << number << " is even";

if (number % 5 == 0)

cout << number << " is multiple of 5";

To find: The output of the code.

Solution:

When the value of the number is 14.

The output of the code will be “14 is even�. In this case, both the ‘if’ statements will be evaluated but only the first ‘if’ statement will be executed.

// Header files

#include

// Header files

#include

//Declaring the namespace

using namespace std;

// Declaring the main of code

int main() {

// Declaring the variable.

int number=14;

// Using the if-statement.

if(number % 2 == 0)

// Displays the message.

cout << number << " is even";

// Using the if-statement.

if(number % 5 == 0)

// Displays the message.

cout << number << " is multiple of 5";

// Using return statement

return 0;

}

When the value of the number is 15.

The output of the code will be “15 is multiple of 5�. In this case, both the ‘if’ statements will be evaluated but only the second ‘if’ statement will be executed.

// Header files

#include

// Header files

#include

//Declaring the namespace

using namespace std;

// Declaring the main of code

int main() {

// Declaring the variable...

(b)

Explanation of Solution

Given: The following code:

if (number % 2 == 0)

cout << number << " is even";

else if (number % 5 == 0)

cout << number <<" is multiple of 5";

To find: The output of the code.

Solution:

When the value of the number is 14.

The output of the code will be “14 is even�. In this case, the ‘else-if’ statement will be evaluated only when the condition of the ‘if’ statement is false. Here, the condition of the ‘if’ statement is true. Hence, only the ‘if’ statement will be executed.

// Header files

#include

// Header files

#include

//Declaring the namespace

using namespace std;

// Declaring the main of code

int main() {

// Declaring the variable.

int number=14;

// Using the if-statement.

if(number % 2 == 0)

// Displays the message.

cout << number << " is even";

// Using the else-if-statement.

else if(number % 5 == 0)

// Displays the message.

cout << number << " is multiple of 5";

// Using return statement

return 0;

}

When the value of the number is 15.

The output of the code will be “15 is multiple of 5�. In this case, the ‘else-if’ statement will be evaluated only when the condition of the ‘if’ statement is false. Here, the condition of the ‘if’ statement is false. Hence, only the ‘else-if’ statement will be executed.

// Header files

#include

// Header files

#include

//Declaring the namespace

using namespace std;

// Declaring the main of code

int main() {

// Declaring the variable...