Chapter 3, Problem 21CP

Explanation of Solution

Given: The following Boolean expressions where x is assumed to be 1:

(true) && (3 > 4)

!(x > 0) && (x > 0)

(x > 0) || (x < 0)

(x != 0) || (x == 0)

(x >= 0) || (x < 0)

(x != 1) == !(x == 1)

To find: The result of the Boolean expressions when x is 1:

(true) && (3 > 4)

!(x > 0) && (x > 0)

(x > 0) || (x < 0)

(x != 0) || (x == 0)

(x >= 0) || (x < 0)

(x != 1) == !(x = =1)

Solution:

The expression (true) && (3 > 4) evaluates to false.

In && operator, both the operands should be true.

3 > 4 is false.

true && false gives false.

Therefore, the result of this expression is false.

The expression or statement !(x > 0) && (x > 0) evaluates to false.

x > 0 is true, which makes !(x > 0) false.

false && true gives false...