Chapter 3, Problem 1PE

(Algebra: solve quadratic equations) The two roots of a quadratic equation $a{x}^2+bx+c=0$ can be obtained using the following formula:

$r_1=\frac{-b+\sqrt{b^2-4ac}}{2a}{\text{and r}}_2=\frac{-b-\sqrt{b^2-4ac}}{2a}$

$b^2-4ac$ is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots.

Write a program that prompts the user to enter values for $a,b,\text{and }c$ and displays the result based on the discriminant. If the discriminant is positive two roots. If the discriminant is 0, display one root. Otherwise, display “The equation has no real roots.�

Note that you can use pow $(\text{x , 0}\text{.5) to compute }\sqrt{x.}$