The resultant matrix by performing the indicated matrix operations. [ 2 1 0 0 5 − 4 ] − 3 [ 5 3 − 6 0 − 2 5 ]

Question

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Answer 1

Question

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

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Answer 2

Question

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

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Answer 3

Question

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

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Answer 4

Question

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

Answer 6

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

Answer 7

Chapter 2.CR, Problem 1CR

To determine

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Answer 8

Expert Solution & Answer

Answer to Problem 1CR

Solution:

[21005−4]−3[53−60−25]=[−13−818011−19]

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information:

[21005−4]−3[53−60−25]

Calculation:

If A and B are the matrices of the same size, then A−B represents the sum of A and (−1)B. That is, A−B=A+(−1)B.

Thus,

[21005−4]−3[53−60−25]=[21005−4]+(−3)[53−60−25]

Now, simplify (−3)[53−60−25] using scalar multiplication.

Definition of scalar multiplication:

If A=[aij] is an m×n matrix and c is a scalar, then the scalar multiple of A by c is the m×n matrix cA=[caij].

Thus,

(−3)[53−60−25]=[−3(5)−3(3)−3(−6)−3(0)−3(−2)−3(5)]

=[−15−91806−15]

Therefore,

[21005−4]+(−3)[53−60−25]=[21005−4]+[−15−91806−15]

Now, both the matrices are of the same size, to add them add their corresponding entries.

Definition of matrix addition:

If A=[aij] and B=[bij] are matrices of size m×n, then their sum is the m×n matrix A+B=[aij+bij].

That is,

[21005−4]+[−15−91806−18]=[2+(−15)1+(−9)0+(18)0+05+6−4+(−15)]

=[−13−818011−19]

Therefore,

[21005−4]−3[53−60−25]=[−13−818011−19]

Answer 12

The resultant matrix by performing the indicated matrix operations. [ 2 1 0 0 5 − 4 ] − 3 [ 5 3 − 6 0 − 2 5 ]

Concept explainers

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The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]

Answer to Problem 1CR

Explanation of Solution

Want to see more full solutions like this?

Chapter 2 Solutions

The resultant matrix by performing the indicated matrix operations. [ 2 1 0 0 5 − 4 ] − 3 [ 5 3 − 6 0 − 2 5 ]

Concept explainers

Videos

The resultant matrix by performing the indicated matrix operations. [21005−4]−3[53−60−25]

Answer to Problem 1CR

Explanation of Solution

Want to see more full solutions like this?

Chapter 2 Solutions

The resultant matrix by performing the indicated matrix operations.

[21005−4]−3[53−60−25]