1st Edition

ISBN: 9781938168000

Author: Paul Peter Urone, Roger Hinrichs

Publisher: OpenStax College

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Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alph…

Textbook Question

Chapter 29, Problem 82PE

Integrated Concepts

A laser with a power output of 2.00 mW at a wavelength of 400 nm is projected onto calcium metal. (a) How many electrons per second are ejected? (b) What power is carried away by the electrons, given that the binding energy is 2.71 eV? (c) Calculate the current of ejected electrons. (d) If the photoelectric material is electrically insulated and acts like a 2.00-pF capacitor, how long will current flow before the capacitor voltage stops it?

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Chapter 29, Problem 81PE

Chapter 29, Problem 83PE

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a) Calculate the number of photoelectrons per second ejected from a 0.75 -mm? area of sodium metal by 295 nm EM radiation having an intensity of 1.30 kW/m² (the intensity of sunlight above the Earth's atmosphere). electrons per second b) Given that the binding energy is 2.20 eV, what power is carried away by the electrons? mW

A HeNe laser generates laser light with an output of 2.00mW and a wavelength of 632.8nm. a) how many photons do the larsen leave every second? b) if the laser beam illuminates an aluminum surface for one minute, which is the maximum number of electrons that can be released during that minute. c) what wavelength would the laser light need to have in order for the shortest de Broglie wavelength of the released electrons to be 548 pm d) if light with the wavelength you calculated in problem c) would illuminate a golden white instead, would you then expect released electrons with a shorter de Broglie wavelength than that in problem c)? Motivate your answer

In the equation above, w is called the work function and it is the minimum energy required to dislodge an electron from the metal's surface. The value of w varies from metal to metal, Using Einstein's formula for the energy of a photon, The work function is related to the threshol frequency (and thresk wave length) as follo we obtain the following expression for the kinetic energy of the ejected electrons: hc w = hv.= (KE), = hv - w = h(v-v This result helped Einstein explained observations (1) and (2). Since (KE). = mv must be greater than zero (i.e. m is positive and v is positive), then we know that v must be greater than ve: Also, a plot of (KE). versus v should be linear and the value of h is obtained from the slope of the line! The value of h was expected to be (and found to be) equal to 6.626x10-34 J s! The "appearance" of h in another physical situation suggested that Planck's quantum hypothesis was not that crazy after all. See p from Example 2-1: A domestic microwave employs…

Chapter 29 Solutions

College Physics

Ch. 29 - Give an example of a physical entity that is...Ch. 29 - Give an example of a physical entity that is not...Ch. 29 - What aspect of the blackbody spectrum forced...Ch. 29 - If Planck's constant were large, say 1034 times...Ch. 29 - Why don't we notice quantization in everyday...Ch. 29 - Is visible light the only type of EM radiation...Ch. 29 - Which aspects of the photoelectric effect cannot...Ch. 29 - Is the photoelectric effect a direct consequence...Ch. 29 - Insulators (nonmetals) have a higher BE than...Ch. 29 - If you pick up and shake a piece of metal that has...

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