1st Edition

ISBN: 9781938168000

Author: Paul Peter Urone, Roger Hinrichs

Publisher: OpenStax College

Concept explainers

Consider an electron of mass m moves with the velocity v in a hydrogen atom. If an electron is at a distance r from the proton, then the potential energy function of the electron can be written as follows:

Isotopes of Hydrogen Atoms

To understand isotopes, it's easiest to learn the simplest system. Hydrogen, the most basic nucleus, has received a great deal of attention. Several of the results seen in more complex nuclei can be seen in hydrogen isotopes. An isotope is a nucleus of t…

Mass of Hydrogen Atom

Hydrogen is one of the most fundamental elements on Earth which is colorless, odorless, and a flammable chemical substance. The representation of hydrogen in the periodic table is H. It is mostly found as a diatomic molecule as water H2O on earth. It is …

Textbook Question

Chapter 29, Problem 14CQ

Tanning salons use "safe" UV with a longer wavelength than some of the UV in sunlight. This "safe" UV has enough photon energy to trigger the tanning mechanism. Is it likely to be able to cause cell damage and induce cancer with prolonged exposure?

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Chapter 29, Problem 13CQ

Chapter 29, Problem 15CQ

Students have asked these similar questions

1. A point source of Co-60 gamma rays emits qual number of photons of 1.17 and 1.33 MeV, giving a flux density of 5.7 × 10⁹ photons/cm² sec at a specified location. What is the energy flux density there, expressed in erg/cm² sec and in J/m² min?

Exposure to a sufficient quantity of ultraviolet light will redden the skin, producing erythema—a sunburn. The amount of exposure necessary to produce this reddening depends on the wavelength. For a 1.0 cm2 patch of skin, 3.7 mJ of ultraviolet light at a wavelength of 254 nm will produce reddening; at 300 nm wavelength, 13 mJ are required.a. What is the photon energy corresponding to each of these wavelengths?b. How many total photons does each of these exposures correspond to?c. Explain why there is a difference in the number of photons needed to provoke a response in the two cases.

1. Derive the relationship between half value layer (HVL) and linear attenuation coefficient (μ). 2. Calculate the thickness of aluminum required to reduce the intensity of a 200 keV gamma-ray beam to 40% of its incident intensity? Assume that the HVL for 200 keV gamma-rays is 2,14 cm Al. 3. Draw a graph to illustrate how a mono-energetic photon beam is attenuated through four HVL thicknesses of Al (Aluminium).

Chapter 29 Solutions

College Physics

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