The mass of the cell, if the radius of a cell in the body is 1.0 × 10 − 5 m , the density is 1000 kg/m 3 , and it absorbs a dose of 1 rad . Given that the cell is shaped like a sphere.

Question

Want to see the full answer?

Answer 1

Question

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.) a C 3.00 με Hh. 6.00 με 20.0 με HE (a) Find the equivalent capacitance between points a and b. 5.92 HF (b) Calculate the charge on each capacitor, taking AV ab = 16.0 V. 20.0 uF capacitor 94.7 6.00 uF capacitor 67.6 32.14 3.00 µF capacitor capacitor C ☑ με με The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC 32.14 ☑ You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC

In the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?

Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.) A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b. (a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µC

Answer 2

Question

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 6

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 7

Chapter 29, Problem 71GP

(a)

To determine

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 8

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 9

(b)

To determine

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 10

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 11

(c)

To determine

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 12

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 13

(d)

To determine

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 29 - Prob. 1RQ Ch. 29 - Prob. 2RQ Ch. 29 - Prob. 3RQ Ch. 29 - Prob. 4RQ Ch. 29 - Prob. 5RQ Ch. 29 - Prob. 6RQ Ch. 29 - Prob. 7RQ Ch. 29 - Prob. 8RQ Ch. 29 - Review Question 29.9 Why are X-rays, gamma rays,...Ch. 29 - Prob. 1MCQ

The mass of the cell, if the radius of a cell in the body is 1.0 × 10 − 5 m , the density is 1000 kg/m 3 , and it absorbs a dose of 1 rad . Given that the cell is shaped like a sphere.

Solution Summary: The author explains the expression for calculating the mass of a body.

Concept explainers

The mass of the cell, if the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

The energy absorbed by a cell in the body, if the radius of the cell is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

The number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of a cell in the body is 1.0×10−5 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

The mass of the absorbing body, the energy absorbed, and the number of ions produced, if the energy needed to produce one positive ion is 100 eV, the radius of the cell is 3.0×10−6 m, the density is 1000 kg/m3, and it absorbs a dose of 1 rad. Given that the cell is shaped like a sphere.

Want to see the full answer?

Chapter 29 Solutions