Chapter 2.9, Problem 6STP

There are 3200 students at Martinsville High School. There are 575 students involved in athletics during the spring athletic seasons. What proportion represents the percent of students not involved in athletics during the spring season? What percent of students is not involved in athletics?

To determine

To determine the percent of students not involved in athletics.

Answer to Problem 6STP

82.23% did not involve in athletics.

Explanation of Solution

Given information :

Total students are 3200.

Students involved in athletics are 575.

Number of students that did not involve in athletics are 3200 − 575 = 2625

Hence the portion of students that did not involve in athletics is $\frac{2625}{3200}$

Percent of students that did not involve in athletics is $\frac{2625}{3200}\times 100=82.23\%$

Hence 82.23% did not involve in athletics.