Chapter 2.4, Problem 11P

Write and solve an equation for each situation. Check your solution.

Tracey is looking at two different travel agencies to plan her vacation. ABC Travel offers a plane ticket for $295 and a rental car for $39 per day. M ** N Travel offers a plane ticket for $350 and a rental car for $33 per day. What is the minimum number of days that Shirley’s vacation should be for M \ N Travel to have the better deal?

To determine

To find : It is being asked to find that the Shirley’s vacation should be for M&N travel to be better deal.

Answer to Problem 11P

Minimum number of days is 10.

Explanation of Solution

Given information: There are two types of travels namely ABC travel and M&N travel.

They offer their own prices. Travel ABC’s fixed cost is $295 and variable cost is $39.

Travel M&N offer fixed cost as $350 and variable cost as $33.

Calculation:

To make M&N travel as better, we need to go for more than some number of days for tour.

Let’s assign variable for number of days we travel as ‘ x’ .

So, total cost for ABC travel is $295+39x$ .

Total cost for M&N travel is $350+33x$

To make M&N travel better deal, we can set up inequality as

  $350+33x\le 295+39x$

Solve the equation for ‘ x’ .

Subtract both sides by 39x

  $350-6x\le 295$

Subtract both sides 350

  $-6x\le -55$

Divide both sides by -6

  $x\ge \mathrm{9.16666...}$

So, minimum number of days the M&N travel to have better deal as more than 9.1666…. So, it is 10 or more days.