Chapter 2.5, Problem 17P

Solve each problem. Round to the nearest tenth, if necessary. Use 3.14 for pi.

A rectangle has perimeter 182 in. and length 52 in. What is the width?

To determine

To find: the width of the given rectangle.

Answer to Problem 17P

The width of the given rectangle is equal to 39 inches.

Explanation of Solution

Given information:

The perimeter of the rectangle = 182 inches

The length of the rectangle = 52 inches

Concept used:

The perimeter of the rectangle is given by

  $=2\left(\text{length}+\text{width}\right)$

Calculation:

Apply the above concept, it gives

  $\begin{array}{l}182=2\left(52+\text{width}\right)\\ 52+\text{width}=\frac{182}{2}\\ 52+\text{width}=91\\ \text{width}=91-52\\ \text{width}=39\text{inches}\end{array}$