Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Question
Chapter 29, Problem 52P
(a)
To determine
To Find: The phase angle
(b)
To determine
To Find:The find the value
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Most signals (responses from transducers, audio, radio waves) are complex waveforms, i.e., a mixture of many frequencies.
Consider a signal that is the sum of two AC voltages at frequencies of 100 Hz and 10 kHz, each with amplitude V。 = 1
Volt. The signal is passed through a low pass filter with time constant ▾ RC = 1 msec. The circuit and input waveform are
shown below:
=
V.
in
ww
R
100 Hz
C
V
10 kHz
WWW
Because the equations describing networks of R's and C's are linear, the voltage across a component is just the sum of its
response to each frequency component separately. Sketch what this (total) output waveform would look like.
At very low frequency, what can be said about the circuit?
R
C
O The current is a small value.
The impedance is very small.
The phase angle between the source voltage and the current is zero.
O None of the above.
O The current going through the circuit is a maximum possible value.
10 Ω
(10 V) cos wt
10 mH
10 μF
Chapter 29 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52PCh. 29 - Prob. 54PCh. 29 - Prob. 55PCh. 29 - Prob. 56PCh. 29 - Prob. 57PCh. 29 - Prob. 58PCh. 29 - Prob. 59PCh. 29 - Prob. 60PCh. 29 - Prob. 61PCh. 29 - Prob. 62PCh. 29 - Prob. 63PCh. 29 - Prob. 64PCh. 29 - Prob. 65PCh. 29 - Prob. 66PCh. 29 - Prob. 67PCh. 29 - Prob. 68PCh. 29 - Prob. 69PCh. 29 - Prob. 70PCh. 29 - Prob. 72PCh. 29 - Prob. 73PCh. 29 - Prob. 74PCh. 29 - Prob. 75PCh. 29 - Prob. 76PCh. 29 - Prob. 77PCh. 29 - Prob. 78PCh. 29 - Prob. 79PCh. 29 - Prob. 80PCh. 29 - Prob. 81PCh. 29 - Prob. 82PCh. 29 - Prob. 83PCh. 29 - Prob. 84PCh. 29 - Prob. 85PCh. 29 - Prob. 86PCh. 29 - Prob. 87PCh. 29 - Prob. 88PCh. 29 - Prob. 89P
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