The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined: 5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’ Concept introduction: DNA stores genetic information in a stable form that can be readily replicated. The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction. The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

The preferred substrate is T because the enzyme half-saturates at 7.00 mM for T, but requires 28.0 mM for U, and 112 mM for S. b Question Content Area The rate constant k 2 with substrate S is 9.60×107 sec-1, with substrate T, k 2 = 6.00×104 sec-1, and with substrate U, k 2 = 2.40×106 sec-1. Calculate the catalytic efficiency with S, T, and U. Catalytic efficiency with S = Catalytic efficiency with T = Catalytic efficiency with U = Does enzyme A use substrate S, substrate T, or substrate U with greater catalytic efficiency?

Fumerase catalyzes the conversion of fumerate to malate. fumerate + H2O ⇋ malate The turnover number, kcat, for fumerase is 8.00×102 sec-1. The Km of this enzyme for fumerate is 5.00×10-3 μmol mL-1. a In an experiment using 2.00×10-3 μmol·mL-1, what is Vmax?

Suppose you wanted to make a buffer of exactly pH 7.00 using KH2PO4 and Na2HPO4. If the final solution was 0.18 M in KH2PO4, you would need 0.25 M Na2HPO4. Now assume you wish to make a buffer at the same pH, using the same substances, but want the total phosphate molarity ([HPO42−]+[H2PO−4]) to equal 0.20 M. What concentration of the Na2HPO4 would be required?

Answer 2

Question

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 6

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 7

Chapter 29, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 12

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 13

Ch. 29 - Prob. 1P Ch. 29 - Prob. 2P Ch. 29 - Prob. 3P Ch. 29 - Prob. 4P Ch. 29 - Prob. 5P Ch. 29 - Prob. 6P Ch. 29 - Prob. 7P Ch. 29 - Prob. 8P Ch. 29 - Prob. 9P Ch. 29 - Prob. 10P

Concept explainers

Videos

Answer to Problem 1P

Explanation of Solution

Want to see more full solutions like this?

Chapter 29 Solutions