Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap
Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap
8th Edition
ISBN: 9780134581064
Author: Bruice, Paula Yurkanis
Publisher: Prentice Hall
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Chapter 28.2, Problem 3P

(a)

Interpretation Introduction

Interpretation: The number of MOs in the given compound 1,3,5,7-Octatetraene has to be given.

Concept introduction:

Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.

Molecular orbitals can be constructed from linear combination of atomic orbitals.

Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.

Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.

Antibonding orbitals have higher energy than the bonding molecular orbitals.

Ground state and and exited states are the positions with lower and higher energy respectively.

HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.

LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.

If the lobes at the ends of the MO are in phase, then the MO is symmetric.

If the two lobes are out phase then the MO is antisymmetric.

Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap, Chapter 28.2, Problem 3P , additional homework tip  1

(b)

Interpretation Introduction

Interpretation: The designation of HOMO for the given molecule’s molecular orbital has to be given.

Concept introduction:

Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.

Molecular orbitals can be constructed from linear combination of atomic orbitals.

Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.

Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.

Antibonding orbitals have higher energy than the bonding molecular orbitals.

Ground state and and exited states are the positions with lower and higher energy respectively.

HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.

LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.

If the lobes at the ends of the MO are in phase, then the MO is symmetric.

If the two lobes are out phase then the MO is antisymmetric.

Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap, Chapter 28.2, Problem 3P , additional homework tip  2

(c)

Interpretation Introduction

Interpretation: Number of nodes in the given molecule has to be given.

Concept introduction:

Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.

Molecular orbitals can be constructed from linear combination of atomic orbitals.

Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.

Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.

Antibonding orbitals have higher energy than the bonding molecular orbitals.

Ground state and and exited states are the positions with lower and higher energy respectively.

HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.

LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.

If the lobes at the ends of the MO are in phase, then the MO is symmetric.

If the two lobes are out phase then the MO is antisymmetric.

Node is the site with zero electron density.

Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap, Chapter 28.2, Problem 3P , additional homework tip  3

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