Explanation The magnetic field produced by the inner solenoid is same as the field produced by the outer solenoid. Whereas the magnetic field inside the smaller solenoid will be equal to the sum of fields from both solenoids. The sum of the two fields is given by, B 1 + B 2 = μ 0 ( − I ) n a + μ 0 I n b (I) Here, μ 0 is the permeability of free space, n a is the number of turns per unit length in the small solenoid, n 2 is the number of turns per unit length in the second solenoid

Physics for Scientists and Engineers with Modern Physics

4th Edition

ISBN: 9780131495081

Author: Douglas C. Giancoli

Publisher: Addison-Wesley

See similar textbooks

Concept explainers

Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 28, Problem 71GP

To determine

The required ratio nbna.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 28, Problem 70GP

Chapter 28, Problem 72GP

Students have asked these similar questions

Is it possible for average velocity to be negative?a. Yes, in cases when the net displacement is negative.b. Yes, if the body keeps changing its direction during motion.c. No, average velocity describes only magnitude and not the direction of motion.d. No, average velocity describes only the magnitude in the positive direction of motion.

Tutorial Exercise An air-filled spherical capacitor is constructed with an inner-shell radius of 6.95 cm and an outer-shell radius of 14.5 cm. (a) Calculate the capacitance of the device. (b) What potential difference between the spheres results in a 4.00-μC charge on the capacitor? Part 1 of 4 - Conceptualize Since the separation between the inner and outer shells is much larger than a typical electronic capacitor with separation on the order of 0.1 mm and capacitance in the microfarad range, we expect the capacitance of this spherical configuration to be on the order of picofarads. The potential difference should be sufficiently low to avoid sparking through the air that separates the shells. Part 2 of 4 - Categorize We will calculate the capacitance from the equation for a spherical shell capacitor. We will then calculate the voltage found from Q = CAV.

I need help figuring out how to do part 2 with the information given in part 1 and putting it in to the simulation. ( trying to match the velocity graph from the paper onto the simulation to find the applied force graph) Using this simulation https://phet.colorado.edu/sims/cheerpj/forces-1d/latest/forces-1d.html?simulation=forces-1d.

Chapter 28 Solutions

Physics for Scientists and Engineers with Modern Physics

Ch. 28.1 - In Example 2510 we saw that a typical lightning...Ch. 28.1 - Suppose both I1 and I2 point into the page in Fig....Ch. 28.4 - Prob. 1CE Ch. 28 - The magnetic field due to current in wires in your...Ch. 28 - Compare and contrast the magnetic field due to a...Ch. 28 - Two insulated long wires carrying equal currents I...Ch. 28 - Prob. 4Q Ch. 28 - A horizontal current-carrying wire, free to move...Ch. 28 - (a) Write Ampres law for a path that surrounds...Ch. 28 - Suppose the cylindrical conductor of Fig. 2811a...

Ch. 28 - Explain why a field such as that shown in Fig....Ch. 28 - Prob. 9Q Ch. 28 - Use the Biot-Savart law to show that the field of...Ch. 28 - Prob. 11Q Ch. 28 - Why does twisting the lead-in wires to electrical...Ch. 28 - Compare the Biot-Savart law with Coulombs law....Ch. 28 - How might you define or determine the magnetic...Ch. 28 - How might you measure the magnetic dipole moment...Ch. 28 - A type of magnetic switch similar to a solenoid is...Ch. 28 - A heavy magnet attracts, from rest, a heavy block...Ch. 28 - Will a magnet attract any metallic object, such as...Ch. 28 - An unmagnetized nail will not attract an...Ch. 28 - Prob. 20Q Ch. 28 - Prob. 21Q Ch. 28 - Prob. 22Q Ch. 28 - Prob. 23Q Ch. 28 - Two iron bars attract each other no matter which...Ch. 28 - Describe the magnetization curve for (a) a...Ch. 28 - Prob. 26Q Ch. 28 - (I) Jumper cables used to start a stalled vehicle...Ch. 28 - (I) If an electric wire is allowed to produce a...Ch. 28 - Prob. 3P Ch. 28 - Prob. 4P Ch. 28 - Prob. 5P Ch. 28 - (II) An experiment on the Earths magnetic field is...Ch. 28 - Prob. 7P Ch. 28 - At the location of the compass, the magnetic field...Ch. 28 - (II) A long horizontal wire carries 24.0 A of...Ch. 28 - (II) A straight stream of protons passes a given...Ch. 28 - (II) Determine the magnetic field midway between...Ch. 28 - (II) Two straight parallel wires are separated by...Ch. 28 - (II) Two long straight wires each carry a current...Ch. 28 - (II) A long pair of insulated wires serves to...Ch. 28 - (II) A third wire is placed in the plane of the...Ch. 28 - (II) A power line carries a current of 95 A west...Ch. 28 - (II) A compass needle points 28 E of N outdoors....Ch. 28 - Prob. 18P Ch. 28 - (II) Let two long parallel wires, a distance d...Ch. 28 - (II) Repeat Problem 19 if the wire at x = 0...Ch. 28 - (II) Two long wires are oriented so that they are...Ch. 28 - (II) Two long parallel wires 8.20 cm apart carry...Ch. 28 - (III) A very long flat conducting strip of width d...Ch. 28 - (III) A triangular loop of side length a carries a...Ch. 28 - Prob. 25P Ch. 28 - Prob. 26P Ch. 28 - (I) A 2.5-mm-diameter copper wire carries a 33-A...Ch. 28 - (II) A toroid (Fig. 2817) has a 50.0-cm inner...Ch. 28 - Prob. 29P Ch. 28 - (II) (a) Use Eq. 281, and the vector nature of B,...Ch. 28 - (II) A coaxial cable consists of a solid inner...Ch. 28 - (III) Suppose the current in the coaxial cable of...Ch. 28 - Prob. 33P Ch. 28 - (II) A wire, in a plane, has the shape shown in...Ch. 28 - (II) A circular conducting ring of radius R is...Ch. 28 - (II) A small loop of wire of radius 1.8 cm is...Ch. 28 - Prob. 37P Ch. 28 - Prob. 38P Ch. 28 - Prob. 39P Ch. 28 - Prob. 40P Ch. 28 - Prob. 41P Ch. 28 - (III) Use the result of Problem 41 to find the...Ch. 28 - (III) A wire is bent into the shape of a regular...Ch. 28 - Prob. 44P Ch. 28 - Prob. 45P Ch. 28 - (III) A square loop of wire, of side d, carries a...Ch. 28 - (II) An iron atom has a magnetic dipole moment of...Ch. 28 - (I) The following are some values of B and B0 for...Ch. 28 - (I) A large thin toroid has 285 loops of wire per...Ch. 28 - (II) An iron-core solenoid is 38 cm long and 1.8...Ch. 28 - Three long parallel wires are 3.5 cm from one...Ch. 28 - Prob. 52GP Ch. 28 - Prob. 53GP Ch. 28 - Prob. 54GP Ch. 28 - Two long straight parallel wires are 15 cm apart....Ch. 28 - A rectangular loop of wire carries a 2.0-A current...Ch. 28 - Prob. 57GP Ch. 28 - A long horizontal wire carries a current of 48 A....Ch. 28 - A square loop of wire, of side d, carries a...Ch. 28 - Prob. 60GP Ch. 28 - Prob. 61GP Ch. 28 - For two long parallel wires separated by a...Ch. 28 - Near the Earths poles the magnetic field is about...Ch. 28 - A 175-g model airplane charged to 18.0 mC and...Ch. 28 - Suppose that an electromagnet uses a coil 2.0 m in...Ch. 28 - Four hour long straight parallel wires located at...Ch. 28 - Prob. 67GP Ch. 28 - A thin 12-cm-long solenoid has a total of 420...Ch. 28 - A 550-turn solenoid is 15 cm long. The current...Ch. 28 - Prob. 70GP Ch. 28 - Prob. 71GP Ch. 28 - Prob. 72GP Ch. 28 - Prob. 73GP Ch. 28 - Prob. 74GP Ch. 28 - (II) A circular current loop of radius 15 cm...Ch. 28 - (III) A set of Helmholtz coils (see Problem 61,...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The required ratio n b n a .

Solution Summary: The author explains that the required ratio is n_b, whereas the magnetic field inside the smaller solenoid is equal to the sum of both solenoids.

Concept explainers

The required ratio nbna.

Want to see the full answer?

Chapter 28 Solutions