A circuit you’re building needs an ammeter that goes from 0 mA to a full-scale reading of 50 mA. Unfortunately, the only ammeter in the storeroom goes from
a. What value of R must you use so that the meter will go to full scale when the current I is 50 mA?
b. What is the effective resistance of your ammeter?
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Chapter 28 Solutions
PHY F/SCIENTIST MOD MASTERING 24 MO
- No chatgpt pls will upvotearrow_forward2. 1. Tube Rating Charts Name: Directions: For the given information state if the technique is safe or unsafe and why. 60 Hertz Stator Operation Effective Focal Spot Size- 0.6 mm Peak Kilovolts MA 2 150 140 130 120 110 100 90 80 70 2501 60 50 40 30 .01 .02 .04.06 .1 .2 .4.6 1 8 10 Maximum Exposure Time In Seconds Is an exposure of 80 kVp, 0.1 second and 200 mA within the limits of the single phase, 0.6 mm focal spot tube rating chart above? Is an exposure of 100 kVp, 0.9 second and 150 mA within the limits of the single phase, 0.6 mm focal spot tube rating chart above?arrow_forwardQ: You have a CO2 laser resonator (λ = 10.6 μm). It has two curved mirrors with R₁=10m, R2= 8m, and mirror separation /= 5m. Find: R2-10 m tl Z-O 12 R1-8 m 1. Confocal parameter. b= 21w2/2 =√1 (R1-1)(R2-1)(R1+R2-21)/R1+R2-21) 2. Beam waist at t₁ & t2- 3. Waist radius (wo). 4. 5. The radius of the laser beam outside the resonator and about 0.5m from R₂- Divergence angle. 6. Radius of curvature for phase front on the mirrors R₁ & R2-arrow_forward
- No chatgpt pls will upvotearrow_forwardSARET CRKS AUTOWAY 12. A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff? 13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming no air resistance, what is the speed of the ball just before it strikes the ground? 14. Estimate (a) how long it took King Kong to fall straight down from the top of the Empire State Building (280m high), and (b) his velocity just before "landing". Useful equations For Constant Velocity: V => D X = V₁t + Xo For Constant Acceleration: Vr = V + at X = Xo+Vot + v=V+2a(X-Xo) \prom = V +V V velocity t = time D Distance X = Final Position Xo Initial Position V = Final Velocity Vo Initial Velocity a = acceleration For free fall Yf = Final Position Yo Initial Position g = 9.80 m $2 For free fall: V = V + gt Y=Yo+Vo t + +gt V,² = V₁²+2g (Y-Yo) V+Vo Vprom= 2 6arrow_forwardSolve the problemsarrow_forward
- A 11 kg weight is attached to a spring with constant k = 99 N/m and subjected to an external force F(t) =-704 sin(5t). The weight is initially displaced 4 meters above equilibrium and given an upward velocity of 5 m/s. Find its displacement for t> 0. y(t) וןarrow_forward7. A race car accelerates from rest to 55 m s-1 in 5.0 seconds. The acceleration of the car Is m s-² 8. An object's speed increases uniformly from 10.5 km per hour to 99.8 km per hour in 2.41 seconds. Calculate the acceleration in m s-2 and express your answer to three significant figures. 9. The acceleration-time graph of a car is shown below. The initial speed of the car is 5.0 m s-1. # Acceleration (ms) 12 8.0- 4.0- 2.0 4.0 6.0 Time (s) Calculate the velocity of the car at t = 4.0 s. 3arrow_forwardNo chatgpt pls will upvotearrow_forward
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