Whether the plaintiff is correct that the magnetic field of the earth is causing the buzzing of the wire or not.

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R₁ 5.0 22 H 4/ a ● R3 78 92 ● £₁ = 24.0 V V 0.10 2 £₂ = 48.0 V 0.50 Ω E3= 6.0 V 13 + 1₂x i 0.05 02 h R₂ ww 40 Ω (a) Apply the junction rule at point a. Use the convention that current leaving a junction is positive and current entering a junction is negative. 1₁x Rs -2002 ✓+13 X e -1₁R₁+E₁-₁₁-1₁ R5+12 R₂+12₂=E₂ = 0 0.20 E = 36.0 V The next two parts of the problem will require you to use the math type box to enter an equation for Kirchhoff's loop rule in terms of variables only. An example problen with what the required formatting should look like for the system to recognize it as a correct answer is provided below. Example: Apply the loop rule to loop abcdelka, using variables instead of values. (i.e. E₁, 12, R₁, r2 etc.). Use the Mathtype Editor (orange box). Use subscripts using the menu in the math editor. The answer is case sensitive (use R and r differently as appropriate). • When forming the product IR, don't forget the multiplication sign. Enter IR as I. R. Solution: ✓ = 0

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Chapter 28, Problem 44AP

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Whether the plaintiff is correct that the magnetic field of the earth is causing the buzzing of the wire or not.

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R₁ 5.0 22 H 4/ a ● R3 78 92 ● £₁ = 24.0 V V 0.10 2 £₂ = 48.0 V 0.50 Ω E3= 6.0 V 13 + 1₂x i 0.05 02 h R₂ ww 40 Ω (a) Apply the junction rule at point a. Use the convention that current leaving a junction is positive and current entering a junction is negative. 1₁x Rs -2002 ✓+13 X e -1₁R₁+E₁-₁₁-1₁ R5+12 R₂+12₂=E₂ = 0 0.20 E = 36.0 V The next two parts of the problem will require you to use the math type box to enter an equation for Kirchhoff's loop rule in terms of variables only. An example problen with what the required formatting should look like for the system to recognize it as a correct answer is provided below. Example: Apply the loop rule to loop abcdelka, using variables instead of values. (i.e. E₁, 12, R₁, r2 etc.). Use the Mathtype Editor (orange box). Use subscripts using the menu in the math editor. The answer is case sensitive (use R and r differently as appropriate). • When forming the product IR, don't forget the multiplication sign. Enter IR as I. R. Solution: ✓ = 0

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