Microbiology: An Introduction
Microbiology: An Introduction
12th Edition
ISBN: 9780321929150
Author: Gerard J. Tortora, Berdell R. Funke, Christine L. Case
Publisher: PEARSON
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Chapter 28, Problem 3CAE

The antibiotic efrotomycin is produced by Streptomyces lactamdurans. S. lactamdurans was grown in 40,000 liters of medium. The medium consisted of glucose, maltose, soybean oil, (NH4)2SO4, NaCl, KH2PO4, and Na2HPO4. The culture was aerated and maintained at 28°C. The following results were obtained from analyses of the culture medium during cell growth:

Chapter 28, Problem 3CAE, The antibiotic efrotomycin is produced by Streptomyces lactamdurans. S. lactamdurans was grown in , example  1

Chapter 28, Problem 3CAE, The antibiotic efrotomycin is produced by Streptomyces lactamdurans. S. lactamdurans was grown in , example  2

  1. a. Under what conditions is the most efrotomycin produced? Is it a primary or secondary metabolite?
  2. b. Which is used first, maltose or glucose? Suggest a reason for this.
  3. c. What is the purpose of each ingredient in the growth medium? (Hint: See Chapter 6.)
  4. d. What is Streptomyces? (Hint: See Chapter 11.)
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Below is shown a growth curve for an E. coli culture. As indicated, the culture was incubated in the absence of a carbon source for 2 hours until Glucose and Lactose were added; Glucose was used up after 5 hours, and Lactose was used up after 8 hours. During the time-course, you take four samples, labeled A-D, after 1, 3, 7 and 9 hours, respectively, as indicated under the graph. Assuming there is cAMP present at t=0, for each sample identify whether CAP and/or the Lac Repressor would be bound to the DNA, and explain why.
Below is shown a growth curve for an E. coli culture. As indicated, the culture was incubated in the absence of a carbon source for 2 hours until Glucose and Lactose were added; Glucose was used up after 5 hours, and Lactose was used up after 8 hours. During the time-course, you take four samples, labeled A-D, after 1, 3, 7 and 9 hours, respectively, as indicated under the graph. Assuming there is cAMP present at t=0, for each sample identify whether CAP and/or the Lac Repressor would be bound to the DNA, and explain why.
The colony forming units (CFU)/ml in sauerkraut brine are given for different types of bacteria except for leuconostoc (shaded column). To obtain the Leuconostoc counts for different days, 40 microlitre of sauerkraut brine was 10-fold diluted and the CFU was determined by plating different dilutions on agar plates. For Day 0 56 CFU were counted in 10-1 dilution, Day 1 81 CFU were counted in 10-3 dilution, Day 2 86 CFU were counted in 10-3 dilution Day 5 78 CFU were counted in 10-5 dilution     Calculate the CFU/ml of leuconostoc in the brine for the 4 different days. Show your calculation

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Microbiology: An Introduction

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