Concept explainers
You are working in your dream job: an assistant for the special effects department of a movie studio. You have just been given this assignment: the star of a horror movie is walking down a spooky hallway when suddenly, due to some unknown and strange supernatural forces, all the pictures hanging on the wall start rotating about their upper edges until they are sticking straight out from the wall! To set up this effect, you attach the pictures to the wall with hinges along their upper end and wrap 20 turns of wire around the outside frame of the picture, as shown in Figure P28.32a. You set up a uniform magnetic field in the hallway that is directed upward and oriented at an angle of γ = 5.00° to the vertical, with its horizontal component directed perpendicularly into the wall. When you send a current of I = 10.0 A through the wire around each picture, the frame swings up perpendicular to the wall as shown in Figure P28.32b. Consider a particular picture of width ω = 40.6 cm, height h = 50.8 cm, and mass m = 0.750 kg. (a) Your supervisor asks you to determine the magnetic field magnitude that is necessary for this picture to rotate so that its face is parallel to the floor and perpendicular to the wall, as in Figure P28.32b. (b) She also asks about any dangers associated with this magnetic field.
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Chapter 28 Solutions
Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term
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- A spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of 3.5 μC. A second spider with a charge of 4.2 μC rests in her own web exactly 2.1 m vertically below the first spider. (a) What is the magnitude of the electric field due to the charge on the second spider at the position of the first spider? 8.57e3 N/C (b) What is the tension in the silk fiber above the first spider? 0.275 How does the electric field relate to the force? How do you calculate the net force? Narrow_forwardPlastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between 91 system of all three beads is zero. E field lines 91 92 93 X What charge does each bead carry? 91 = 92 = ?2.9 0 μC × What is the net charge of the system? What charges have to be equal? μC 93 2.9 με and 93. The sum of the charge on 91 and 92 is 91 +92 = -2.9 μC, and the net charge of thearrow_forwardAn electron has an initial speed of 5.26 x 100 m/s in a uniform 5.73 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity not enough information to decide × What is the direction of the force on the electron? How does it compare to the direction of the electric field, considering the sign of the electron's charge? (b) How far does the electron travel before coming to rest? 0.0781 × What kinematic equation is relevant here? How do you calculate the force due to the electric field? m (c) How long does it take the electron to come to rest? 5.27e8 What is the final velocity of the electron? s (d) What is the electron's speed when it returns to its starting point? 5.26e6 m/sarrow_forward
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