Two components in an HPLC separation have retention times that differ by 15 s. The first peak elutes in 9.0 min, and the peak widths are approximately equal. The dead time to was 65 s. Use a spreadsheet to find the minimum number of theoretical plates needed to achieve the following resolution. R. values: 0.50 0.75, 0.90, 1.0, 1.10. 1.25, 1.50. L75. 2.0 and 2.5. How would the results change if peak 2 were twice as broad as peak 1
Two components in an HPLC separation have retention times that differ by 15 s. The first peak elutes in 9.0 min, and the peak widths are approximately equal. The dead time to was 65 s. Use a spreadsheet to find the minimum number of theoretical plates needed to achieve the following resolution. R. values: 0.50 0.75, 0.90, 1.0, 1.10. 1.25, 1.50. L75. 2.0 and 2.5. How would the results change if peak 2 were twice as broad as peak 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Two components in an HPLC separation have retention times that differ by 15 s. The first peak elutes in 9.0 min, and the peak widths are approximately equal. The dead time to was 65 s. Use a spreadsheet to find the minimum number of theoretical plates needed to achieve the following resolution. R. values: 0.50 0.75, 0.90, 1.0, 1.10. 1.25, 1.50. L75. 2.0 and 2.5. How would the results change if peak 2 were twice as broad as peak 1?
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