Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 28, Problem 27PQ
What is the electric field in an aluminum wire if the drift speed of the free electrons in the wire is measured to be 4.50 × 10–5 m/s? The resistivity of aluminum is
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3.) The graph shows how current I varies with potential difference V across a component X.
904
80-
70-
60-
50-
I/MA
40-
30-
20-
10-
0+
0
0.5
1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
VIV
Component X and a cell of negligible internal resistance are placed in a circuit.
A variable resistor R is connected in series with component X. The ammeter reads 20mA.
4.0V
4.0V
Component X and the cell are now placed in a potential divider circuit.
(a) Outline why component X is considered non-ohmic. [1]
(b(i)) Determine the resistance of the variable resistor. [3]
(b(ii)) Calculate the power dissipated in the circuit. [1]
(c(i)) State the range of current that the ammeter can measure as the slider S of the potential divider
is moved from Q to P. [1]
(c(ii)) Describe, by reference to your answer for (c)(i), the advantage of the potential divider
arrangement over the arrangement in (b).
1.) Two long parallel current-carrying wires P and Q are separated by 0.10 m. The current in wire P is 5.0 A.
The magnetic force on a length of 0.50 m of wire P due to the current in wire Q is 2.0 × 10-s N.
(a) State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P. [2]
(b) Calculate the current in wire Q. [2]
(c) Another current-carrying wire R is placed parallel to wires P and Q and halfway between them as shown.
wire P
wire R
wire Q
0.05 m
0.05 m
The net magnetic force on wire Q is now zero.
(c.i) State the direction of the current in R, relative to the current in P.[1]
(c.ii) Deduce the current in R. [2]
2.) A 50.0 resistor is connected to a cell of emf 3.00 V. The voltmeter and the ammeter in the circuit are ideal.
V
A
50.00
(a) The current in the ammeter is 59.0 mA. Calculate the internal resistance of the cell.
The circuit is changed by connecting another resistor R in parallel to the 50.0 resistor.
V
A
50.00
R
(b) Explain the effect of this change on R is made of a resistive wire of uniform cross-sectional area 3.1 × 10-8 m²,
resistivity 4.9 × 10-70m and length L. The resistance of R is given by the equation
R = KL
where k is a constant.
(b.i) the reading of the ammeter. [2]
(b.ii) the reading of the voltmeter. [2]
(c) Calculate k. State an appropriate unit for your answer. [3]
[2]
Chapter 28 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 28.1 - Prob. 28.1CECh. 28.2 - Prob. 28.2CECh. 28.3 - Prob. 28.3CECh. 28.5 - When a lightbulb burns out, its filament breaks so...Ch. 28.6 - A battery with terminal potential is connected to...Ch. 28.7 - A battery of terminal potential is connected to a...Ch. 28 - Prob. 1PQCh. 28 - Prob. 2PQCh. 28 - Prob. 3PQCh. 28 - Prob. 4PQ
Ch. 28 - Prob. 5PQCh. 28 - Prob. 6PQCh. 28 - Prob. 7PQCh. 28 - Prob. 8PQCh. 28 - Prob. 9PQCh. 28 - Prob. 10PQCh. 28 - Prob. 11PQCh. 28 - Prob. 12PQCh. 28 - Prob. 13PQCh. 28 - Prob. 14PQCh. 28 - The current in a wire varies with time (measured...Ch. 28 - Prob. 16PQCh. 28 - The amount of charge that flows through a copper...Ch. 28 - Prob. 18PQCh. 28 - Prob. 19PQCh. 28 - Prob. 20PQCh. 28 - Prob. 21PQCh. 28 - Prob. 22PQCh. 28 - A copper wire that is 2.00 mm in radius with...Ch. 28 - Prob. 24PQCh. 28 - Prob. 25PQCh. 28 - Prob. 26PQCh. 28 - What is the electric field in an aluminum wire if...Ch. 28 - Prob. 28PQCh. 28 - Prob. 29PQCh. 28 - Prob. 30PQCh. 28 - Prob. 31PQCh. 28 - Prob. 32PQCh. 28 - Two concentric, metal spherical shells of radii a...Ch. 28 - Prob. 34PQCh. 28 - Prob. 35PQCh. 28 - Prob. 36PQCh. 28 - Prob. 37PQCh. 28 - A lightbulb is connected to a variable power...Ch. 28 - Prob. 39PQCh. 28 - Prob. 40PQCh. 28 - Prob. 41PQCh. 28 - Prob. 42PQCh. 28 - Prob. 43PQCh. 28 - A Two wires with different resistivities, 1 and 2,...Ch. 28 - A copper and a gold wire are supposed to have the...Ch. 28 - Gold bricks are formed with the dimensions 7358134...Ch. 28 - Prob. 47PQCh. 28 - Prob. 48PQCh. 28 - Prob. 49PQCh. 28 - Prob. 50PQCh. 28 - Prob. 51PQCh. 28 - Prob. 52PQCh. 28 - Prob. 53PQCh. 28 - Prob. 54PQCh. 28 - A two-slice bread toaster consumes 850.0 W of...Ch. 28 - Prob. 56PQCh. 28 - Prob. 57PQCh. 28 - Prob. 58PQCh. 28 - Prob. 59PQCh. 28 - Prob. 60PQCh. 28 - Prob. 61PQCh. 28 - Prob. 62PQCh. 28 - Prob. 63PQCh. 28 - Prob. 64PQCh. 28 - Prob. 65PQCh. 28 - Prob. 66PQCh. 28 - Prob. 67PQCh. 28 - Prob. 68PQCh. 28 - Prob. 69PQCh. 28 - Prob. 70PQCh. 28 - Prob. 71PQCh. 28 - Prob. 72PQCh. 28 - Prob. 73PQCh. 28 - Prob. 74PQCh. 28 - Review When a metal rod is heated, its resistance...Ch. 28 - Prob. 76PQCh. 28 - Prob. 77PQCh. 28 - Prob. 78PQCh. 28 - Prob. 79PQCh. 28 - Prob. 80PQCh. 28 - Prob. 81PQCh. 28 - A conducting material with resistivity is shaped...
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