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(a)
Interpretation:
The reason the systematic name
Concept introduction:
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
(b)
Interpretation:
The reason the systematic name cadmium nitrate for
Concept introduction:
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
(c)
Interpretation:
The reason the formula
Concept introduction:
The general rules for writing the systematic names of ionic compounds are as follows:
1) In binary ionic compounds, the name of the metal is written as the original name whereas the name of the non-metal has the root word with the suffix
2) In metals that form more than one ion, the Latin root of the metal is followed by a suffix
3) In the family of two oxoanions, the ion with more oxygen atoms has the non-metal root and a suffix
4) For hydrated ionic compounds, the total number of water molecules are represented by the Greek numerical prefixes followed by the word hydrate.
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Chapter 2 Solutions
Chemistry: The Molecular Nature of Matter and Change - Standalone book
- ASP.....arrow_forwardQuestion 7 (10 points) Identify the carboxylic acid present in each of the following items and draw their structures: Food Vinegar Oranges Yogurt Sour Milk Pickles Acid Structure Paragraph ✓ BI UAE 0118 + v Task: 1. Identify the carboxylic acid 2. Provide Name 3. Draw structure 4. Take a picture of your table and insert Add a File Record Audio Record Video 11.arrow_forwardCheck the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 IZ IN Molecule 4 Molecule 5 ZI none of the above ☐ Molecule 3 Х IN www Molecule 6 NH Garrow_forward
- Highlight each chiral center in the following molecule. If there are none, then check the box under the drawing area. There are no chiral centers. Cl Cl Highlightarrow_forwardA student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forwardटे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forward
- Shown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forwardNG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forward
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