
Concept explainers
(a)
Interpretation:
The correct scenes that represent a mixture that fills a container is to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not
(a)

Answer to Problem 2.127P
The scenes that represent a mixture that fills a container are D and E.
Explanation of Solution
In the image D, an element and a compound are present which are not chemically bonded to each other. In the image E, a mixture of two elements is present which fills up the container.
The scenes that represent a mixture that fills a container are D and E.
(b)
Interpretation:
The scenes that represent a substance that cannot be broken down into simpler ones, are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(b)

Answer to Problem 2.127P
The scenes that represent a substance that cannot be broken down into simpler ones are A, C, G and I.
Explanation of Solution
A substance that cannot be broken down into simpler ones is called an element.
The scenes A and C depict polyatomic elements. In polyatomic elements, two or more atoms of the same element are bonded to each other. For example, sulfur. The element sulfur is also found in the octatomic state in which 8 atoms of sulfur are bonded to each other.
The scene G depicts a diatomic element whereas the scene I depicts a monatomic element.
The scenes that represent a substance that cannot be broken down into simpler ones are A, C, G and I.
(c)
Interpretation:
The scenes that represent an element with very high resistance to flow are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(c)

Answer to Problem 2.127P
The scene that represents an element with high resistance to flow is A.
Explanation of Solution
The scenes that represent elements are A, C, G and I
The resistance to flow is called viscosity. The viscosity of a matter is dependent on its state. Gases have the lowest viscosity whereas solids have the highest viscosity. Therefore, gases have the least resistance to their flow whereas solids have the highest resistance to flow.
Among A, C, G and I, C is a liquid whereas G and I are gases. In scene A, the element has a fixed shape and volume. These are the characteristics of a solid. Therefore, scene A represents an element with high resistance to flow.
The scene that represents an element with high resistance to flow is A.
(d)
Interpretation:
The scenes that represent a homogenous mixture, are to be determined
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other.
Mixtures can be classified as homogenous and heterogeneous mixtures. Homogenous mixtures are those which have a uniform composition. The components of a homogenous mixture cannot be seen separately through the eyes. Heterogeneous mixtures do not have a uniform composition. The components of a heterogeneous mixture can be seen separately and hence can be easily separated.
(d)

Answer to Problem 2.127P
The scenes that represent a homogenous mixture are E and H.
Explanation of Solution
In scene E, the two gaseous elements are a homogenous mixture. Since the phase of the mixture is the same (gaseous), hence it is impossible to see them separately through the eyes.
In scene H, the homogenous mixture is a mixture of two liquids. Since the phase of the mixture is the same (gaseous), hence it is a homogenous mixture.
The scenes that represent a homogenous mixture are E and H.
(e)
Interpretation:
The scenes that represent an element that conforms to the walls of its container and displays an upper surface are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(e)

Answer to Problem 2.127P
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
Explanation of Solution
An element may exist in solid, liquid and gaseous forms. Among the solids, liquids, and gases, the liquids conform to the walls of its container and display an upper surface.
The scenes that represent an element are A, C, G and I. The element in scene A is solid. The elements in scenes g and I are gases. The element in scene C is a liquid. Therefore scene C represents an element that conforms to the walls of its container and displays an upper surface.
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
(e)
Interpretation:
The scenes that represent an element that conforms to the walls of its container and displays an upper surface are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(e)

Answer to Problem 2.127P
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
Explanation of Solution
An element may exist in solid, liquid and gaseous forms. Among the solids, liquids, and gases, the liquids conform to the walls of its container and display an upper surface.
The scenes that represent an element are A, C, G and I. The element in scene A is solid. The elements in scenes g and I are gases. The element in scene C is a liquid. Therefore scene C represents an element that conforms to the walls of its container and displays an upper surface.
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
(f)
Interpretation:
The scenes that represent a gas that consists of diatomic particles are to be determined.
Concept introduction:
The matter is anything that has mass and occupies space. The three
Solids – Solids are those substances in which the constituent particles are tightly packed. Solids have a fixed shape and volume.
Liquids – Liquids are those substances in which the constituent particles are loosely packed compared to those of the solids but tighter than those of the gases. Liquids take the shape of the container they fill.
Gases – Gases are those substances in which the constituent particles are free to move around. Gases neither have a definite shape nor a definite volume.
(f)

Answer to Problem 2.127P
The scenes that represent a gas that consists of diatomic particles are B and G.
Explanation of Solution
The scenes that represent the gaseous states are B, D, E, F, G and I.
In the scenes D, E and I, the gases are monatomic. The gas in scene I is triatomic. The gases in scenes B and G are diatomic.
The scenes that represent a gas that consists of diatomic particles are B and G.
(g)
Interpretation:
The scenes that represent a gas that consists of diatomic particles are to be determined.
Concept introduction:
The matter is anything that has mass and occupies space. The three states of matter are as follows:
Solids – Solids are those substances in which the constituent particles are tightly packed. Solids have a fixed shape and volume.
Liquids – Liquids are those substances in which the constituent particles are loosely packed compared to those of the solids but tighter than those of the gases. Liquids take the shape of the container they fill.
Gases – Gases are those substances in which the constituent particles are free to move around. Gases neither have a definite shape nor a definite volume.
(g)

Answer to Problem 2.127P
The scenes that represent a gas that consists of diatomic particles are B and G.
Explanation of Solution
The scenes that represent the gaseous states are B, D, E, F, G and I.
In the scenes D, E and I, the gases are monatomic. The gas in scene I is triatomic. The gases in scenes B and G are diatomic.
The scenes that represent a gas that consists of diatomic particles are B and G.
(h)
Interpretation:
The scene that represents a substance with a
Concept introduction:
The law of definite composition - This law can be defined as; a particular compound maintains an exact universal proportion of elements in its composition, irrespective of the source. The proposal for this law was made by Joseph Proust.
(h)

Answer to Problem 2.127P
The scene that represents a substance with a
Explanation of Solution
In scene F, the gaseous compound is formed by the combination of two white balls representing atoms of one kind with one blue ball representing an atom of another kind. Here the ratio of the white balls to the blue ball is
The scene that represents a substance with a
(i)
Interpretation:
The scenes that represent a matter that can be separated into its component substances by physical means, are to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other. The components of a mixture do not lose their individual identity. The components of a mixture are not chemically bonded to each other. Therefore, the mixture components can be separated using the physical methods.
(i)

Answer to Problem 2.127P
The scenes that represent a matter that can be separated into its component substances by physical means, are D, E, and H.
Explanation of Solution
The substances which can be separated into their components by physical methods are called mixtures.
The scenes A, C, Gand I represent elements in their pure forms. Scenes B and F represent compounds in their pure forms. Scene D represents a mixture of a gas and a liquid. Scene E represents, a mixture of two gases. Scene H represents a mixture of two liquids.
The scenes that represent a matter that can be separated into its component substances by physical means, are D, E, and H.
(j)
Interpretation:
The scene that represents a heterogeneous mixture is to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other.
Mixtures can be classified as homogenous and heterogeneous mixtures. Homogenous mixtures are those which have a uniform composition. The components of a homogenous mixture cannot be seen separately through the eyes. Heterogeneous mixtures do not have a uniform composition. The components of a heterogeneous mixture can be seen separately and hence can be easily separated.
(j)

Answer to Problem 2.127P
The scene that represents a heterogeneous mixture is D.
Explanation of Solution
The scenes that represent a mixture are D, E and H. The scene E represents a homogenous mixture of two gases whereas the scene h represents a homogenous mixture of two liquids. Scene D represents a heterogeneous mixture since a boundary of distinction is visible for the two components of the mixture.
The scene that represents a heterogeneous mixture is D.
(k)
Interpretation:
The scenes that represent matter that obeys the law of definite composition are to be determined.
Concept introduction:
The law of definite composition - This law can be defined as; a particular compound maintains an exact universal proportion of elements in its composition, irrespective of the source. The proposal for this law was made by Joseph Proust.
(k)

Answer to Problem 2.127P
The scenes that represent matter that obeys the law of definite composition are B and F.
Explanation of Solution
The scenes that represent compounds are B and F. In scene B, the red and yellow balls represent two different atoms which have combined in the
The scenes that represent matter that obeys the law of definite composition are B and F.
Want to see more full solutions like this?
Chapter 2 Solutions
Chemistry: The Molecular Nature of Matter and Change - Standalone book
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H H CH3OH, H+ H Select to Add Arrows H° 0:0 'H + Q HH ■ Select to Add Arrows CH3OH, H* H. H CH3OH, H+ HH ■ Select to Add Arrows i Please select a drawing or reagent from the question areaarrow_forwardWhat are examples of analytical methods that can be used to analyse salt in tomato sauce?arrow_forwardA common alkene starting material is shown below. Predict the major product for each reaction. Use a dash or wedge bond to indicate the relative stereochemistry of substituents on asymmetric centers, where applicable. Ignore any inorganic byproducts H Šali OH H OH Select to Edit Select to Draw 1. BH3-THF 1. Hg(OAc)2, H2O =U= 2. H2O2, NaOH 2. NaBH4, NaOH + Please select a drawing or reagent from the question areaarrow_forward
- What is the MOHR titration & AOAC method? What is it and how does it work? How can it be used to quantify salt in a sample?arrow_forwardPredict the major products of this reaction. Cl₂ hv ? Draw only the major product or products in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If there will be no products because there will be no significant reaction, just check the box under the drawing area and leave it blank. Note for advanced students: you can ignore any products of repeated addition. Explanation Check Click and drag to start drawing a structure. 80 10 m 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility DII A F1 F2 F3 F4 F5 F6 F7 F8 EO F11arrow_forwardGiven a system with an anodic overpotential, the variation of η as a function of current density- at low fields is linear.- at higher fields, it follows Tafel's law.Calculate the range of current densities for which the overpotential has the same value when calculated for both cases (the maximum relative difference will be 5%, compared to the behavior for higher fields).arrow_forward
- Using reaction free energy to predict equilibrium composition Consider the following equilibrium: N2 (g) + 3H2 (g) = 2NH3 (g) AGº = -34. KJ Now suppose a reaction vessel is filled with 8.06 atm of nitrogen (N2) and 2.58 atm of ammonia (NH3) at 106. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of N2 tend to rise or fall? ☐ x10 fall Is it possible to reverse this tendency by adding H₂? In other words, if you said the pressure of N2 will tend to rise, can that be changed to a tendency to fall by adding H2? Similarly, if you said the pressure of N will tend to fall, can that be changed to a tendency to rise by adding H₂? If you said the tendency can be reversed in the second question, calculate the minimum pressure of H₂ needed to reverse it. Round your answer to 2 significant digits. yes no ☐ atm Х ด ? olo 18 Ararrow_forwardFour liters of an aqueous solution containing 6.98 mg of acetic acid were prepared. At 25°C, the measured conductivity was 5.89x10-3 mS cm-1. Calculate the degree of dissociation of the acid and its ionization constant.Molecular weights: O (15.999), C (12.011), H (1.008).Limiting molar ionic conductivities (λ+0 and λ-0) of Ac-(aq) and H+(aq): 40.9 and 349.8 S cm-2 mol-1.arrow_forwardDetermine the change in Gibbs energy, entropy, and enthalpy at 25°C for the battery from which the data in the table were obtained.T (°C) 15 20 25 30 35Eo (mV) 227.13 224.38 221.87 219.37 216.59Data: n = 1, F = 96485 C mol–1arrow_forward
- Indicate the correct options.1. The units of the transport number are Siemens per mole.2. The Siemens and the ohm are not equivalent.3. The Van't Hoff factor is dimensionless.4. Molar conductivity does not depend on the electrolyte concentration.arrow_forwardIdeally nonpolarizable electrodes can1. participate as reducers in reactions.2. be formed only with hydrogen.3. participate as oxidizers in reactions.4. form open and closed electrochemical systems.arrow_forwardIndicate the options for an electrified interface:1. Temperature has no influence on it.2. Not all theories that describe it include a well-defined electrical double layer.3. Under favorable conditions, its differential capacitance can be determined with the help of experimental measurements.4. A component with high electronic conductivity is involved in its formation.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





