Explanation Given that, the functions are y 1 = cos x and y n = sin ( x + h ) − sin x h . Consider the function y n = sin ( x + h ) − sin x h . Substitute n = 2 and h = 0.5 in y n = sin ( x + h ) − sin x h and obtain the function y 2 as follows. y n = sin ( x + h ) − sin x h y 2 = sin ( x + 0.5 ) − sin x 0.5 Substitute n = 3 and h = 0.1 in y n = sin ( x + h ) − sin x h and obtain the function y 3 as follows. y n = sin ( x + h ) − sin x h y 3 = sin ( x + 0

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

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Chapter 27.1, Problem 42E

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To graph: The functions y1=cosx and yn=sin(x+h)−sinxh for 0≤x≤2π with n=2,h=0.5 and n=3,h=0.1.

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Chapter 27.1, Problem 41E

Chapter 27.1, Problem 43E

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Chapter 27 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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To graph: The functions y 1 = cos x and y n = sin ( x + h ) − sin x h for 0 ≤ x ≤ 2 π with n = 2 , h = 0.5 and n = 3 , h = 0.1 .

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To graph: The functions y1=cosx and yn=sin(x+h)−sinxh for 0≤x≤2π with n=2,h=0.5 and n=3,h=0.1.

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Chapter 27 Solutions