Explanation Formula used: 1. d ( sin − 1 u ) d x = 1 1 − u 2 ⋅ d u d x 2. d ( x n ) d x = n x n − 1 Calculation: The given function is y = 5 x sin − 1 2 x + 1 − 4 x 2 . Find the derivative of y = 5 x sin − 1 2 x + 1 − 4 x 2 as follows. d y d x = 5 { sin − 1 ( 2 x ) d d x ( x ) + x d d x ( sin − 1 ( 2 x ) ) } + d d x ( 1 − 4 x 2 ) 1 2 = 5 { sin − 1 ( 2 x ) ⋅ ( 1 ) + x ⋅ 1 1 − ( 2 x ) 2

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 27.3, Problem 15E

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The derivative of the function y=5xsin−12x+1−4x2.

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Chapter 27.3, Problem 14E

Chapter 27.3, Problem 16E

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Chapter 27 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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The derivative of the function y = 5 x sin − 1 2 x + 1 − 4 x 2 .

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The derivative of the function y=5xsin−12x+1−4x2.

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