Explanation Formula used: The derivative of ln u is d ( ln u ) d x = 1 u d u d x . The derivative of sin u is d ( sin u ) d x = cos u d u d x . Calculation: Evaluate the derivative of h = 4 ln sin 6 θ 3 as follows. h = 4 ln sin 6 θ 3 d h d θ = 4 sin 6 θ 3 ⋅ 1 3 ( sin 6 θ )

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 27, Problem 28RE

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The derivative of h=4lnsin6θ3.

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Chapter 27, Problem 27RE

Chapter 27, Problem 29RE

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Chapter 27 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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The derivative of h = 4 ln sin 6 θ 3 .

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The derivative of h=4lnsin6θ3.

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Chapter 27 Solutions