University Physics (14th Edition)
14th Edition
ISBN: 9780133969290
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 27, Problem Q27.14DQ
To determine
To check: All forces on the particle of the accelerator are the magnetic force.
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Why must the electrical polarity of the tubes in a linear accelerator be reversed at very short time intervals?
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Only charged particles can be accelerated in a
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Chapter 27 Solutions
University Physics (14th Edition)
Ch. 27 - Can a charged particle move through a magnetic...Ch. 27 - Prob. Q27.2DQCh. 27 - Section 27.2 describes a procedure for finding the...Ch. 27 - The magnetic force on a moving charged particle is...Ch. 27 - A charged particle is fired into a cubical region...Ch. 27 - If the magnetic force does no work on a charged...Ch. 27 - A charged particle moves through a region of space...Ch. 27 - How might a loop of wire carrying a current be...Ch. 27 - How could the direction of a magnetic field be...Ch. 27 - A loose, floppy loop of wire is carrying current...
Ch. 27 - Prob. Q27.11DQCh. 27 - Each of the lettered points at the corners of the...Ch. 27 - A student claims that if lightning strikes a metal...Ch. 27 - Prob. Q27.14DQCh. 27 - The magnetic force acting on a charged particle...Ch. 27 - When the polarity of the voltage applied to a dc...Ch. 27 - Prob. Q27.17DQCh. 27 - Prob. Q27.18DQCh. 27 - A particle with a charge of 1.24 108C is moving...Ch. 27 - A particle of mass 0.195 g carries a charge of...Ch. 27 - In a 1.25-T magnetic field directed vertically...Ch. 27 - A particle with mass 1.81 103 kg and a charge of...Ch. 27 - An electron experiences a magnetic force of...Ch. 27 - An electron moves at 1.40 106m/s through a region...Ch. 27 - CP A particle with charge 7.80 C is moving with...Ch. 27 - CP A particle with charge 5.60 nC is moving in a...Ch. 27 - A group of particles is traveling in a magnetic...Ch. 27 - A flat, square surface with side length 3.40 cm is...Ch. 27 - A circular area with a radius of 6.50 cm lies in...Ch. 27 - A horizontal rectangular surface has dimensions...Ch. 27 - An open plastic soda bottle with an opening...Ch. 27 - Prob. 27.14ECh. 27 - An election at point A in Fig. E27.15 has a speed...Ch. 27 - Repeat Exercise 27.15 for the case in which the...Ch. 27 - CP A 150-g ball containing 4.00 108 excess...Ch. 27 - An alpha particle (a He nucleus, containing two...Ch. 27 - In an experiment with cosmic rays, a vertical beam...Ch. 27 - BIO Cyclotrons are widely used in nuclear medicine...Ch. 27 - Prob. 27.21ECh. 27 - In a cyclotron, the orbital radius of protons with...Ch. 27 - An electron in the beam of a cathode-ray tube is...Ch. 27 - A beam of protons traveling at 1.20 km/s enters a...Ch. 27 - A proton (q = 1.60 1019 C, m = 1.67 1027 kg)...Ch. 27 - A singly charged ion of 7Li (an isotope of...Ch. 27 - Prob. 27.27ECh. 27 - Prob. 27.28ECh. 27 - A 150-V battery is connected across two parallel...Ch. 27 - A singly ionized (one electron removed) 40K atom...Ch. 27 - Singly ionized (one electron removed) atoms are...Ch. 27 - In the Bainbridge mass spectrometer (see Fig....Ch. 27 - Prob. 27.33ECh. 27 - A straight, 2.5-m wire carries a typical household...Ch. 27 - A long wire carrying 4.50 A of current makes two...Ch. 27 - An electromagnet produces a magnetic field of...Ch. 27 - A thin, 50.0-cm-long metal bar with mass 750 g...Ch. 27 - A straight, vertical wire carries a current of...Ch. 27 - Prob. 27.39ECh. 27 - The plane of a 5.0 cm X 8.0 cm rectangular loop of...Ch. 27 - The 20.0 cm 35.0 cm rectangular circuit shown in...Ch. 27 - A rectangular coil of wire, 22.0 cm by 35.0 cm and...Ch. 27 - CP A uniform rectangular coil of total mass 212 g...Ch. 27 - Both circular coils A and B (Fig. E27.44) have...Ch. 27 - Prob. 27.45ECh. 27 - Prob. 27.46ECh. 27 - Prob. 27.47ECh. 27 - A dc motor with its rotor and field coils...Ch. 27 - Figure E27.49 shows a portion of a silver ribbon...Ch. 27 - Prob. 27.50ECh. 27 - When a particle of charge q 0 moves with a...Ch. 27 - A particle with charge 7.26 108C is moving in a...Ch. 27 - Prob. 27.53PCh. 27 - Prob. 27.54PCh. 27 - Prob. 27.55PCh. 27 - The magnetic poles of a small cyclotron produce a...Ch. 27 - A particle with negative charge q and mass m =...Ch. 27 - A particle of charge q 0 is moving at speed in...Ch. 27 - Suppose the electric field between the plates in...Ch. 27 - Mass Spectrograph. A mass spectrograph is used to...Ch. 27 - A straight piece of conducting wire with mass M...Ch. 27 - CP A 2.60-N metal bar, 0.850 m long and having a...Ch. 27 - BIO Determining Diet. One method for determining...Ch. 27 - CP A plastic circular loop has radius R, and a...Ch. 27 - Prob. 27.65PCh. 27 - A wire 25.0 cm long lies along the z-axis and...Ch. 27 - A long wire carrying 6.50 A of current makes two...Ch. 27 - The rectangular loop shown in Fig. P27.68 is...Ch. 27 - Prob. 27.69PCh. 27 - Prob. 27.70PCh. 27 - The loop of wire shown in Fig. P27.71 forms a...Ch. 27 - CP A uniform bar has mass 0.0120 kg and is 30.0 cm...Ch. 27 - CALC A Voice Coil. It was shown in Section 27.7...Ch. 27 - Prob. 27.74PCh. 27 - CALC Force on a Current Loop in a Nonuniform...Ch. 27 - Quark Model of the Neutron. The neutron is a...Ch. 27 - A circular loop of wire with area A lies in the...Ch. 27 - DATA You are using a type of mass spectrometer to...Ch. 27 - Prob. 27.79PCh. 27 - DATA You are a technician testing the operation of...Ch. 27 - A particle with charge 2.15 C and mass 3.20 1011...Ch. 27 - Prob. 27.82CPCh. 27 - If a proton is exposed to an external magnetic...Ch. 27 - BIO MAGNETIC FIELDS AND MRI. Magnetic resonance...Ch. 27 - The large magnetic fields used in MRI can produce...
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- Check Your Understanding A cyclotron is to be designed to accelerate protons to kinetic energies of 20 Mev using a magnetic field of 2.0 T. What is the required radius of the cyclotron?arrow_forwardThe creation and study of new and very massive elementary particles is an important part of contemporary physics. To create a particle of mass M requires an energy Mc2 . With enough energy, an exotic particle can be created by allowing a fast-moving proton to collide with a similar target particle. Consider a perfectly inelastic collision between two protons: an incident proton with mass kinetic energy K, and momentum magnitude p joins with an originally stationary target proton to form a single product particle of mass M. Not all the kinetic energy of the incoming proton is available to create the product particle because conservation of momentum requires that the system as a whole still must have some kinetic energy after the collision. Therefore, only a fraction of the energy of the incident particle is available to create a new particle. (a) Show that the energy available to create a product particle is given by Mc2=2mpc21+K2mpc2 This result shows that when the kinetic energy K of the incident proton is large compared with its rest energy mpc2, 2then M approaches (2mpK)1/2/c. Therefore, if the energy of the incoming proton is increased by a factor of 9, the mass you can create increases only by a factor of 3, not by a factor of 9 as would be expected. (b) This problem can be alleviated by using colliding beams as is the case in most modern accelerators. Here the total momentum of a pair of interacting particles can be zero. The center of mass can be at rest after the collision, so, in principle, all the initial kinetic energy can be used for particle creation. Show that Mc2=2mc2(1+Kmc2) where K is the kinetic energy of each of the two identical colliding particles. Here, if k mc2, we have M directly proportional to K as we would desire.arrow_forwardIn the figure, the weight of the 20 cm long moving edge of a frame in the vertical plane in a magnetic field of B=0.57 out of the paper plane is W=0.1 N. The total of the frame is R=10 Q. What will be the limit velocity of the released edge? - 20cm a) v = 160 m/s b) V = 100 m/s c) V = 220 m/s d) O v= 55 m/s %3! O 0 00 QO 00 © 0 00 0 0 00arrow_forward
- A cyclotron used to accelerate protons has a maximum radius of 0.4 m and the magnetic induction used is one tesla. Find the frequency of oscillator connected to the dees and the maximum velocity of emerging protons. Through what P.D. must the protons be accelerated from rest to achieve this speed? If deuterons are used instead of protons, what would be their final energy? Mp= 1.67 x 10-27 kg.arrow_forwardAs a charged particle is shot to a magnetic field B with a speed v perpendicular to B, the particle's motion gets modified and the so called "cyclotron radius" relates to its charge as /9 b. q? O inversely O directlyarrow_forwardA linear accelerator can be used to accelerate which of the following? protons and electrons U protons and neutrons O protons only protons, electrons, and neutronsarrow_forward
- (a) A beam of highly energetic protons emerges from a cyclotron. Can you assume that there is a magnetic field associated with these particles? Justify your answer. (b) When a current travels through the coils of a coil spring, the coil contracts as if it were compressed. What is your explanation for the fact?arrow_forward27. A cyclotron (Fig. 29.16) designed to accelerate pro- tons has an outer radius of 0.350 m. The protons are emitted nearly at rest from a source at the center and are accelerated through 600 V each time they cross the gap between the dees. The dees are between the poles of an electromagnet where the field is 0.800 T. (a) Find the cyclotron frequency for the protons inarrow_forwardAI answered the problem this way. Is this correct? The Lorentz force that makes a charged particle move in a circular path in a magnetic field is given by F=qvBF=qvB where qq is the charge of the particle, vv is the speed of the particle, and BB is the magnetic field strength. Since the particle is moving in a circular path, this force must equal the centripetal force, F=mv2rF=rmv2, where mm is the mass of the particle and rr is the radius of the circular path. Setting the two expressions for FF equal to each other, we get qvB=mv2rqvB=rmv2 Since we want to find the frequency of the orbit, we need to find the speed vv of the proton. Given that the energy of the proton is 1 MeV, we can write 12mv2=1 MeV21mv2=1MeV and solve for vv: v=2×1 MeVmv=m2×1MeV where mm is the mass of a proton, which is approximately 1.67×10−27 kg1.67×10−27kg. Substituting this expression for vv into the expression for the Lorentz force, we can solve for the frequency of the orbit. The frequency is related to…arrow_forward
- All final answer must be up to the 3rd decimal places with the appropriate units. (a) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength magnetic field is needed to hold antiprotons, moving at 5.00 ×107 m/s in a circular path 2.00 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge. (b) Is this field strength obtainable with today’s technology or is it a futuristic possibility?arrow_forwardAs a charged particle is shot to a magnetic field B with a speed v perpendicular to B, the particle's motion gets modified and the so called "cyclotron radius" relates to its charge directly inversely O as vaarrow_forwardDerive a formula for the time taken for a charged particle of mass m, charge q moving at velocity v in a radius r in a magnetic field B to do half a cycle in a cyclotron.arrow_forward
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