Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 27, Problem 74AP
(a)
To determine
The proof of the statement that the current is given by the equation
(b)
To determine
The analogous rules relating the direction of the
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A close analogy exists between the flow of energy by heat because
of a temperature difference (see Section 19.6) and the flow of
electric charge because of a potential difference. In a metal,
energy dQ and electrical charge dq are both transported by free
electrons. Consequently, a good electrical conductor is usually a
good thermal conductor as well. Consider a thin conducting slab
of thickness dx, area A, and electrical conductivity o, with a
potential difference dVbetween opposite faces. (a) Show that the
current I= dq| dt is given by the equation on the left:
Charge conduction Thermal conduction
da
= GA
dt
dQ
= kA
dx
dt
dx
In the analogous thermal conduction equation on the right (Eq.
19.17), the rate dQ/ dt of energy flow by heat (in SI units of joules
per second) is due to a temperature gradient dT/ dx in a material of
thermal conductivity k. (b) State analogous rules relating the
direction of the electric current to the change in potential and
relating the direction of energy…
A close analogy exists between the flow of energy by heat
because of a temperature difference (see Section 19.6) and
the flow of electric charge because of a potential difference.
In a metal, energy dQ and electrical charge dq are both
transported by free electrons. Consequently, a good electri-
cal conductor is usually a good thermal conductor as well.
Consider a thin conducting slab of thickness dx, area A,
and electrical conductivity ơ, with a potential difference dV
between opposite faces. (a) Show that the current I = dq/dt
is given by the equation on the left:
Charge conduction
Thermal conduction
dq
= oA
dt
dT
kA
dt
dQ
AP
dx
dx
In the analogous thermal conduction equation on the right
(Eq. 19.17), the rate dQ/dt of energy flow by heat (in SI units
of joules per second) is due to a temperature gradient
dT/dx in a material of thermal conductivity k. (b) State anal-
ogous rules relating the direction of the electric current to
the change in potential and relating the direction of…
A close analogy exists between the flow of energy by heat because of a temperature difference (see Section 20.7) and the
flow of electric charge because of a potential difference. In a metal, energy dQ and electrical charge dq are both
transported by free electrons. Consequently, a good electrical conductor is usually a good thermal conductor as well.
Consider a thin conducting slab of thickness dx, area A, and electrical conductivity o, with a potential difference dv
between opposite faces. (a) Show that the current I = dq/dt is given by the equation on the left:
Charge conduction Thermal conduction
dq
TA
dt
JdT|
kA
dt
dQ
| dx
|AP|
|dx
In the analogous thermal conduction equation on the right (Eq. 20.15), the rate dQ/dt of energy flow by heat (in Sl units of
joules per second) is due to a temperature gradient dT/dx in a material of thermal conductivity k. (b) State analogous rules
relating the direction of the electric current to the change in potential and relating the direction of…
Chapter 27 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 27.1 - Consider positive and negative charges of equal...Ch. 27.2 - Prob. 27.2QQCh. 27.2 - Prob. 27.3QQCh. 27.4 - When does an incandescent lightbulb carry more...Ch. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1OQCh. 27 - Prob. 2OQCh. 27 - Prob. 3OQCh. 27 - Prob. 4OQCh. 27 - Prob. 5OQ
Ch. 27 - Prob. 6OQCh. 27 - Prob. 7OQCh. 27 - Prob. 8OQCh. 27 - Prob. 9OQCh. 27 - Prob. 10OQCh. 27 - Prob. 11OQCh. 27 - Prob. 12OQCh. 27 - Prob. 13OQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQCh. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 1PCh. 27 - A small sphere that carries a charge q is whirled...Ch. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - The quantity of charge q (in coulombs) that has...Ch. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - A wire 50.0 m long and 2.00 mm in diameter is...Ch. 27 - A 0.900-V potential difference is maintained...Ch. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - While taking photographs in Death Valley on a day...Ch. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - At what temperature will aluminum have a...Ch. 27 - Assume that global lightning on the Earth...Ch. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - The potential difference across a resting neuron...Ch. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Prob. 43PCh. 27 - Prob. 44PCh. 27 - Prob. 45PCh. 27 - Prob. 46PCh. 27 - Prob. 47PCh. 27 - Prob. 48PCh. 27 - Prob. 49PCh. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - Prob. 53PCh. 27 - Prob. 54PCh. 27 - Prob. 55PCh. 27 - Prob. 56PCh. 27 - Prob. 57APCh. 27 - Prob. 58APCh. 27 - Prob. 59APCh. 27 - Prob. 60APCh. 27 - Prob. 61APCh. 27 - Prob. 62APCh. 27 - Prob. 63APCh. 27 - Review. An office worker uses an immersion heater...Ch. 27 - Prob. 65APCh. 27 - Prob. 66APCh. 27 - Prob. 67APCh. 27 - Prob. 68APCh. 27 - Prob. 69APCh. 27 - Prob. 70APCh. 27 - Prob. 71APCh. 27 - Prob. 72APCh. 27 - Prob. 73APCh. 27 - Prob. 74APCh. 27 - Prob. 75APCh. 27 - Prob. 76APCh. 27 - Review. A parallel-plate capacitor consists of...Ch. 27 - The dielectric material between the plates of a...Ch. 27 - Prob. 79APCh. 27 - Prob. 80APCh. 27 - Prob. 81APCh. 27 - Prob. 82CPCh. 27 - Prob. 83CPCh. 27 - Material with uniform resistivity is formed into...Ch. 27 - Prob. 85CP
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