Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 27, Problem 55P
To determine
The time interval during which the temperature of
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The heating element of a coffeemaker operates at 120 V and carries a current of 5.00 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat
0.545 kg of water from room temperature (23.0°C) to the boiling point.
min
The heating element of a coffeemaker operates at 120 V and carries a current of 7.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.252 kg of water from room temperature (23.0°C) to the boiling point.
Step 1
The energy required to raise the temperature of an amount of water of mass m, from T;
= 23.0°C to the boiling point, T = 100°C, is
Q = m„C„(AT),
where the specific heat of water c = 4186 J/kg · °C. We have
Q = mwCw(AT) = mwCw(T – T;)
0.252
0.252 kg
4186 J/kg · °C
77
7기 °C
= 0.81225
x 105 J.
0.812
Step 2
The rate P at which the heating element converts electrical potential energy into the internal energy of the water is
P = (AV)I = (|120
120 V
v7.7
7.7 A
= 924
924 J/s.
Step 3
Thus, the time At required to bring the water to a boil is
105 J)
At =
J/s
1 min
min.
60.0 s.
The heating element of a coffeemaker operates at 120 V and carries a current of 7.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.252 kg of water from room temperature (23.0°C) to the boiling point.
Step 1
The energy required to raise the temperature of an amount of water of mass m, from T; = 23.0°C to the boiling point, T = 100°C, is
Q = mC„(AT),
where the specific heat of water c = 4186 J/kg · °C. We have
Q = m„Cw(AT) = m„Cw(T – T;)
0.252
0.252 kg )( 4186 J/kg · °C
77
77 °c)
0.81225
0.812 x 10° J.
Step 2
The rate P at which the heating element converts electrical potential energy into the internal energy of the water is
P = (AV)I =
A
J/s.
=
Chapter 27 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 27.1 - Consider positive and negative charges of equal...Ch. 27.2 - Prob. 27.2QQCh. 27.2 - Prob. 27.3QQCh. 27.4 - When does an incandescent lightbulb carry more...Ch. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1OQCh. 27 - Prob. 2OQCh. 27 - Prob. 3OQCh. 27 - Prob. 4OQCh. 27 - Prob. 5OQ
Ch. 27 - Prob. 6OQCh. 27 - Prob. 7OQCh. 27 - Prob. 8OQCh. 27 - Prob. 9OQCh. 27 - Prob. 10OQCh. 27 - Prob. 11OQCh. 27 - Prob. 12OQCh. 27 - Prob. 13OQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQCh. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 1PCh. 27 - A small sphere that carries a charge q is whirled...Ch. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - The quantity of charge q (in coulombs) that has...Ch. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - A wire 50.0 m long and 2.00 mm in diameter is...Ch. 27 - A 0.900-V potential difference is maintained...Ch. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - While taking photographs in Death Valley on a day...Ch. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - At what temperature will aluminum have a...Ch. 27 - Assume that global lightning on the Earth...Ch. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - The potential difference across a resting neuron...Ch. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Prob. 43PCh. 27 - Prob. 44PCh. 27 - Prob. 45PCh. 27 - Prob. 46PCh. 27 - Prob. 47PCh. 27 - Prob. 48PCh. 27 - Prob. 49PCh. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - Prob. 53PCh. 27 - Prob. 54PCh. 27 - Prob. 55PCh. 27 - Prob. 56PCh. 27 - Prob. 57APCh. 27 - Prob. 58APCh. 27 - Prob. 59APCh. 27 - Prob. 60APCh. 27 - Prob. 61APCh. 27 - Prob. 62APCh. 27 - Prob. 63APCh. 27 - Review. An office worker uses an immersion heater...Ch. 27 - Prob. 65APCh. 27 - Prob. 66APCh. 27 - Prob. 67APCh. 27 - Prob. 68APCh. 27 - Prob. 69APCh. 27 - Prob. 70APCh. 27 - Prob. 71APCh. 27 - Prob. 72APCh. 27 - Prob. 73APCh. 27 - Prob. 74APCh. 27 - Prob. 75APCh. 27 - Prob. 76APCh. 27 - Review. A parallel-plate capacitor consists of...Ch. 27 - The dielectric material between the plates of a...Ch. 27 - Prob. 79APCh. 27 - Prob. 80APCh. 27 - Prob. 81APCh. 27 - Prob. 82CPCh. 27 - Prob. 83CPCh. 27 - Material with uniform resistivity is formed into...Ch. 27 - Prob. 85CP
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