Chapter 27, Problem 13P

To determine

Momentum of the photon of yellow light.

Answer to Problem 13P

Solution: Momentum of the photon of yellow lightis $1.14\times {10}^{-27}\text{kg-m/s}$ .

Explanation of Solution

Given:

The wavelength of the yellow light, $\lambda =5.80\times {10}^{-7}\text{m}$ .

Formula used:

The momentum is calculated by the formula

  $p=\frac{h}{\lambda }$

Here,

  $h=6.62\times {10}^{-34}\text{J-s}$ is the Planck’s constant

  $\lambda$ is the wavelength

Calculation:

The momentum is calculated as

  $p=\frac{h}{\lambda }$

Plugging the values in the above equation

  $\begin{array}{c}p=\frac{6.62\times {10}^{-34}}{5.80\times {10}^{-7}}\end{array}$

   $\begin{array}{c}=1.14\times {10}^{-27}\text{kg-m/s}\end{array}$

Conclusion:

The momentum of the photon of yellow lightis $1.14\times {10}^{-27}\text{kg-m/s}$ .