EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 27, Problem 10RQ
What is the difference between photochemical blanking and chemical blanking?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
B: Solid rotating shaft used in the boat with high speed shown in Figure. The amount of power transmitted at the
greatest torque is 224 kW with 130 r.p.m. Used DE-Goodman theory to determine the shaft diameter. Take the
shaft material is annealed AISI 1030, the endurance limit of 18.86 kpsi and a factor of safety 1. Which criterion
is more conservative?
Note: all dimensions in mm.
1
AA
Motor
300
Thrust
Bearing
Sprocket
100
9750
เอ
Q2: The plate material of a pressure vessel is AISI 1050 QT 205 °C. The plate is rolled to a
diameter of 1.2 m. The two sides of the plate are connected via a riveted joint as shown below. If
the rivet material is G10500 with HB=197 and all rivet sizes M31. Find the required rivet size
when the pressure vessel is subjected to an internal pressure of 500 MPa. Take safety factor = 2.
1.2m
A
B'
A
Chope
olm
10.5
0.23
hope
Continuity equation
A
y
x
dx
D
T
معادلة الاستمرارية
Ly
X
Q/Prove that
ди
хе
+ ♥+ ㅇ?
he
me
ze
ོ༞“༠ ?
Chapter 27 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 27 - Describe the similarities and differences between...Ch. 27 - Name the processes involved in chemical machining....Ch. 27 - Explain the difference between chemical machining...Ch. 27 - What is the underlying principle of...Ch. 27 - Explain how the EDM process is capable of...Ch. 27 - What are the important features of the Blue Arc...Ch. 27 - What are the capabilities of wire EDM? Could this...Ch. 27 - Explain why laser Microjet has a large depth of...Ch. 27 - Describe the advantages of water-jet machining.Ch. 27 - What is the difference between photochemical...
Ch. 27 - What type of workpiece is not suitable for...Ch. 27 - What is an undercut? Why must it be considered in...Ch. 27 - Explain the principle of hybrid machining.Ch. 27 - Give technical and economic reasons that the...Ch. 27 - Why is the preshaping or premachining of parts...Ch. 27 - Explain why the mechanical properties of workpiece...Ch. 27 - Prob. 17QLPCh. 27 - Prob. 18QLPCh. 27 - Why has electrical-discharge machining become so...Ch. 27 - Prob. 20QLPCh. 27 - Which of the advanced machining processes would...Ch. 27 - Which of the processes described in require a...Ch. 27 - Describe your thoughts regarding the laser-beam...Ch. 27 - Are deburring operations still necessary for some...Ch. 27 - List and explain factors that contribute to a poor...Ch. 27 - What is the purpose of the abrasives in...Ch. 27 - Which of the processes described in this chapter...Ch. 27 - Is kerf width important in wire EDM? Explain.Ch. 27 - Comment on your observations regarding Fig. 27.4.Ch. 27 - Why may different advanced machining processes...Ch. 27 - A 200-mm-deep hole that is 30 mm in diameter is...Ch. 27 - If the operation in Problem 27.31 were performed...Ch. 27 - A cutting-off operation is being performed with a...Ch. 27 - A 0.80-in.-thick copper plate is being machined by...Ch. 27 - Explain why it is difficult to produce sharp...Ch. 27 - Make a list of the processes described in this...Ch. 27 - Would the processes described in this chapter be...Ch. 27 - Prob. 38SDPCh. 27 - Describe your thoughts as to whether the...Ch. 27 - Make a list of machining processes that may be...Ch. 27 - At what stage is the abrasive in abrasive...Ch. 27 - Describe the similarities and differences among...Ch. 27 - Describe the similarities and differences among...Ch. 27 - Describe any workpiece size limitations in...Ch. 27 - Suggest several design applications for the types...Ch. 27 - Based on the topics covered in Parts III and IV,...Ch. 27 - Review Example 27.1 and explain the relevant...Ch. 27 - Precision engineering is a term that is used to...Ch. 27 - With appropriate sketches, describe the principles...Ch. 27 - Make a table of the process capabilities of the...Ch. 27 - One of the general concerns regarding advanced...Ch. 27 - It can be seen that several of the processes...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q Derive (continuity equation)? I want to derive clear mathematics.arrow_forwardmotor supplies 200 kW at 6 Hz to flange A of the shaft shown in Figure. Gear B transfers 125 W of power to operating machinery in the factory, and the remaining power in the shaft is mansferred by gear D. Shafts (1) and (2) are solid aluminum (G = 28 GPa) shafts that have the same diameter and an allowable shear stress of t= 40 MPa. Shaft (3) is a solid steel (G = 80 GPa) shaft with an allowable shear stress of t = 55 MPa. Determine: a) the minimum permissible diameter for aluminum shafts (1) and (2) b) the minimum permissible diameter for steel shaft (3). c) the rotation angle of gear D with respect to flange A if the shafts have the minimum permissible diameters as determined in (a) and (b).arrow_forwardFirst monthly exam Gas dynamics Third stage Q1/Water at 15° C flow through a 300 mm diameter riveted steel pipe, E-3 mm with a head loss of 6 m in 300 m length. Determine the flow rate in pipe. Use moody chart. Q2/ Assume a car's exhaust system can be approximated as 14 ft long and 0.125 ft-diameter cast-iron pipe ( = 0.00085 ft) with the equivalent of (6) regular 90° flanged elbows (KL = 0.3) and a muffler. The muffler acts as a resistor with a loss coefficient of KL= 8.5. Determine the pressure at the beginning of the exhaust system (pl) if the flowrate is 0.10 cfs, and the exhaust has the same properties as air.(p = 1.74 × 10-3 slug/ft³, u= 4.7 x 10-7 lb.s/ft²) Use moody chart (1) MIDAS Kel=0.3 Q3/Liquid ammonia at -20°C is flowing through a 30 m long section of a 5 mm diameter copper tube(e = 1.5 × 10-6 m) at a rate of 0.15 kg/s. Determine the pressure drop and the head losses. .μ= 2.36 × 10-4 kg/m.s)p = 665.1 kg/m³arrow_forward
- 2/Y Y+1 2Cp Q1/ Show that Cda Az x P1 mactual Cdf Af R/T₁ 2pf(P1-P2-zxgxpf) Q2/ A simple jet carburetor has to supply 5 Kg of air per minute. The air is at a pressure of 1.013 bar and a temperature of 27 °C. Calculate the throat diameter of the choke for air flow velocity of 90 m/sec. Take velocity coefficient to be 0.8. Assume isentropic flow and the flow to be compressible. Quiz/ Determine the air-fuel ratio supplied at 5000 m altitude by a carburetor which is adjusted to give an air-fuel ratio of 14:1 at sea level where air temperature is 27 °C and pressure is 1.013 bar. The temperature of air decreases with altitude as given by the expression The air pressure decreases with altitude as per relation h = 19200 log10 (1.013), where P is in bar. State any assumptions made. t = ts P 0.0065harrow_forward36 2) Use the method of MEMBERS to determine the true magnitude and direction of the forces in members1 and 2 of the frame shown below in Fig 3.2. 300lbs/ft member-1 member-2 30° Fig 3.2. https://brightspace.cuny.edu/d21/le/content/433117/viewContent/29873977/Viewarrow_forwardCan you solve this for me?arrow_forward
- 5670 mm The apartment in the ground floor of three floors building in Fig. in Baghdad city. The details of walls, roof, windows and door are shown. The window is a double glazing and air space thickness is 1.3cm Poorly Fitted-with Storm Sash with wood strip and storm window of 0.6 cm glass thickness. The thickness of door is 2.5 cm. The door is Poor Installation. There are two peoples in each room. The height of room is 280 cm. assume the indoor design conditions are 25°C DBT and 50 RH, and moisture content of 8 gw/kga. The moisture content of outdoor is 10.5 gw/kga. Calculate heat gain for living room : الشقة في الطابق الأرضي من مبنى ثلاثة طوابق في مدينة بغداد يظهر في مخطط الشقة تفاصيل الجدران والسقف والنوافذ والباب. النافذة عبارة عن زجاج مزدوج وسمك الفراغ الهوائي 1.3 سم ضعيف الاحكام مع ساتر حماية مع إطار خشبي والنافذة بسماكة زجاج 0.6 سم سماكة الباب 2.5 سم. الباب هو تركيب ضعيف هناك شخصان في كل غرفة. ارتفاع الغرفة 280 سم. افترض أن ظروف التصميم الداخلي هي DBT25 و R50 ، ومحتوى الرطوبة 8…arrow_forwardHow do i solve this problem?arrow_forwardQ4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of 250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction between the belt and the small pulley is 0.3, and between the belt and the large pulley is 0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³. (a) What is the power capacity of the drive and (b) If the small pulley replaced by V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of friction between belt and grooved pulley is 0.35. What will be the power capacity in this case, assuming that the diameter of the large pulley remain the same of 1500 mm.arrow_forward
- You are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure. The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application: Specifications: Motor Power: The electric motor provides 10 kW of power at 1,500 RPM. Output Speed: The output shaft should rotate at 150 rpm. Design Decisions: Transmission ratio: Determine the necessary drive ratio for the system. Shaft Diameter: Design the shafts for both the motor and the conveyor end. Material Selection: Choose appropriate materials for the gears, shafts. Bearings: Select suitable rolling element bearings. Constraints: Space Limitation: The available space for the gear drive system is limited to a 1-meter-long section. Attribute 4 of CEP Depth of knowledge required Fundamentals-based, first principles analytical approach…arrow_forward- | العنوان In non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and v.-15mm/s. Calculate: (1) area reduction RA, (2) drawing velocity v. Knowing that: ti: final thickness V. Fig. (1) ofthrearrow_forwardA direct extrusion operation produces the cross section shown in Fig. (2) from an aluminum billet whose diameter 160 mm and length - 700 mm. Determine the length of the extruded section at the end of the operation if the die angle -14° 60 X Fig. (2) Note: all dimensions in mm.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Types of Manufacturing Process | Manufacturing Processes; Author: Magic Marks;https://www.youtube.com/watch?v=koULXptaBTs;License: Standard Youtube License