Concept explainers
(a)
To determine: The amino acid replacements that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements that cannot be the result of a single-base mutation.
Introduction:
The codons UUU, UUC, UUA, and UUG codes for the amino acid phenylalanine and the codons CUU, CUC, CUA and CUG codes for the amino acids leucine.
(b)
To determine: The amino acid replacements that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements which cannot be the result of a single-base mutation.
Introduction:
The lysine and alanine both are amino acids and are found in the human body. The lysine is encoded by AAA and AAG codons. The codons GGU, GCC, GGA and GCG encodes for alanine.
(c)
To determine: The amino acids replacement that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements which cannot be the result of a single-base mutation.
Introduction:
The codons which code for alanine amino acid are GCU, GCC, GCA, and GCG. The codons which code for threonine are ACU, ACC, ACA and ACG. The last two bases in the codons are similar in amino acids, alanine and threonine.
(d)
To determine: The amino acid replacements that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements which cannot be the result of a single-base mutation.
Introduction:
The codons which code for amino acid phenylalanine are UUU, UUC, UUA and UUG. Lysine is encoded by the codons AAA and AAG. The conversion does not involve the change in the single base.
(e)
To determine: The amino acid replacements that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements which cannot be result of a single-base mutation.
Introduction:
The amino acid isoleucine is encoded by the amino acids AUU and AUA. The amino acid leucine is encoded by codons CUU, CUC and CUA. The change in the single base pair and whole bases are same in both amino acids.
(f)
To determine: The amino acid replacements that would be consistent with the genetic code if the replacements were caused by a single base change and amino acid replacements which cannot be the result of a single-base mutation. Give reason.
Introduction:
The amino acid histidine is encoded by the codons CAU and CAC. The amino acid glutamic acid is encoded by the codons GAA and GAG. All bases are different in both the amino acids.
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Chapter 27 Solutions
SAPLINGPLUS FOR PRINCIPLES OF BIOCHEMIS
- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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