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ORG CHEM CONNECT CARD
6th Edition
ISBN: 9781264860746
Author: SMITH
Publisher: MCG
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Chapter 26.8, Problem 19P
Interpretation Introduction

(a)

Interpretation: The products formed by the treatment of β-D-galactose with Ag2O, CH3I are to be drawn.

Concept introduction: The OH groups of monosaccharides on reaction with base and an alkyl halide convert into ether. A single product is formed during this reaction because the configuration of all substituents in the starting material is retained.

Interpretation Introduction

(b)

Interpretation: The products formed by the treatment of β-D-galactose with NaH+C6H5CH2Cl are to be drawn.

Concept introduction: The OH groups of monosaccharides on reaction with base and an alkyl halide convert into ether. A single product is formed during this reaction because the configuration of all substituents in the starting material is retained.

Interpretation Introduction

(c)

Interpretation: The products formed by the treatment of β-D-galactose with NaH+C6H5CH2Cl and then H3O+ are to be drawn.

Concept introduction: The characteristic bond of glycoside is O. A hemiacetal converts into acetal when a monosaccharide is treated with alcohol and HCl. The acetal formed is known as glycoside. The hydrolysis of glycoside generates two compounds that have OH group.

Interpretation Introduction

(d)

Interpretation: The products formed by the treatment of β-D-galactose with Ac2O+pyridine are to be drawn.

Concept introduction: The OH groups of monosaccharides on reaction with anhydride and acetyl chloride convert into ether in the presence of base. A single product is formed during this reaction because the configuration of all substituents in the starting material is retained.

Interpretation Introduction

(e)

Interpretation: The products formed by the treatment of D- galactose with C6H5COCl+pyridine are to be drawn.

Concept introduction: The OH groups of monosaccharides on reaction with anhydride and acetyl chloride convert into ether in the presence of base. A single product is formed during this reaction because the configuration of all substituents in the starting material is retained.

Interpretation Introduction

(f)

Interpretation: The products formed by the treatment of β-D-galactose with NaH+C6H5CH2Cl+H3O+ and then C6H5COCl+pyridine are to be drawn.

Concept introduction: The OH groups of monosaccharides on reaction with anhydride and acetyl chloride convert into ether in the presence of base. A single product is formed during this reaction because the configuration of all substituents in the starting material is retained.

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Students have asked these similar questions
Draw the products formed when ß-D-galactose is treated with each reagent.a. Ag2O + CH3Ib. NaH + C6H5CH2Clc. The product in (b), then H3O+d. Ac2O + pyridinee. C6H5COCl + pyridinef. The product in (c), then C6H5COCl + pyridine
Draw the products formed when β-D-galactose is treated with each reagent. a. Ag2O + CH3I b. NaH + C6H5CH2Cl c. The product in (b), then H3O+ d. Ac2O + pyridine e. C6H5COCl + pyridine f. The product in (c), then C6H5COCl + pyridine
D-Arabinose can exist in both pyranose and furanose forms.a. Draw the a and ß anomers of D-arabinofuranose.b. Draw the a and ß anomers of D-arabinopyranose

Chapter 26 Solutions

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