(a)
Interpretation:
Structure of lecithin and the naturally occurring enantiomer need to be drawn and if phosphodiester is in C2 position will there be chirality has to be discussed.
Concept introduction:
Phosphoglycerides are same as triglycerides but the only difference is that in triglycerides there are three fatty acid residues. But in phosphoglyceride one of the fatty acid residue in triglyceride is replaced by a phosphoester. Hydrolysis of phosphoglycerides yield glycerol, fatty acid, phosphate.
To draw: the structure of lecithin
(b)
Interpretation:
Structure of lecithin and the naturally occurring enantiomer need to be drawn and if phosphodiester is in C2 position will there be chirality has to be discussed.
Concept Introduction:
Chirality is the ability of the compound to rotate the plane polarized light when it is passed through them. A chiral center is the one when the carbon atom is attached to a four different groups. If the plane polarized light is rotated clockwise then the compound is said to be dextrorotatory and if it is anti-clockwise then the compound is levorotatory.
(c)
Interpretation:
Structure of lecithin and the naturally occurring enantiomer need to be drawn and if phosphodiester is in C2 position will there be chirality has to be discussed.
Concept Introduction:
Chirality is the ability of the compound to rotate the plane polarized light when it is passed through them. A chiral center is the one when the carbon atom is attached to a four different groups. If the plane polarized light is rotated clockwise then the compound is said to be dextrorotatory and if it is anti-clockwise then the compound is levorotatory. If the carbon is not attached to four different groups means then it is said to be achiral.
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Chapter 26 Solutions
ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY
- 4. Read paragraph 4.15 from your textbook, use your calculated lattice energy values for CuO, CuCO3 and Cu(OH)2 an explain thermal decomposition reaction of malachite: Cu2CO3(OH)2 →2CuO + H2O + CO2 (3 points)arrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forwardIII O Organic Chemistry Using wedges and dashes in skeletal structures Draw a skeletal ("line") structure for each of the molecules below. Be sure your structures show the important difference between the molecules. key O O O O O CHON Cl jiii iiiiiiii You can drag the slider to rotate the molecules. Explanation Check Click and drag to start drawing a structure. Q Search X G ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use F 3 W C 3/5arrow_forward
- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
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