Structure of optically inactive triglyceride need to be drawn from the given glycerol, one equivalent of palmitic acid and two equivalents of myristic acid and also to check whether the formed triglyceride will react with molecular hydrogen. Concept introduction: Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis. From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol. Molecular hydrogen will react with unsaturated compounds to reduce them. If the compound does not have any unsaturation then that compound wont react with molecular hydrogen. To draw: the structure of optically active triglyceride from the given problem statement.

Question

Want to see the full answer?

Answer 1

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 26, Problem 32PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol, one equivalent of palmitic acid and two equivalents of myristic acid and also to check whether the formed triglyceride will react with molecular hydrogen.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

Molecular hydrogen will react with unsaturated compounds to reduce them. If the compound does not have any unsaturation then that compound wont react with molecular hydrogen.

To draw: the structure of optically active triglyceride from the given problem statement.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Arrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5) Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them. ▸ View Available Hint(s) Least acidity NH&F NaBr NaOH NH,Br NaCIO Reset Greatest acidity

1. Consider the following molecular-level diagrams of a titration. O-HA molecule -Aion °° о ° (a) о (b) (c) (d) a. Which diagram best illustrates the microscopic representation for the EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium. hydroxide? (e)

Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…

Answer 2

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 26, Problem 32PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol, one equivalent of palmitic acid and two equivalents of myristic acid and also to check whether the formed triglyceride will react with molecular hydrogen.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

Molecular hydrogen will react with unsaturated compounds to reduce them. If the compound does not have any unsaturation then that compound wont react with molecular hydrogen.

To draw: the structure of optically active triglyceride from the given problem statement.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 26, Problem 32PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol, one equivalent of palmitic acid and two equivalents of myristic acid and also to check whether the formed triglyceride will react with molecular hydrogen.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

Molecular hydrogen will react with unsaturated compounds to reduce them. If the compound does not have any unsaturation then that compound wont react with molecular hydrogen.

To draw: the structure of optically active triglyceride from the given problem statement.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 26, Problem 32PP

Interpretation Introduction