Concept explainers
(a)
Interpretation: The enantiomer of D-fructose is to be drawn.
Concept introduction: A sugar molecule in which hydroxyl group of second last carbon atom is on the left and right side of the horizontal line is known as
(b)
Interpretation: An epimer of D-fructose at
Concept introduction: Two compounds which are neither superimposable nor mirror images to each other and the configuration of one of their stereogenic centers is different are known as epimers.
(c)
Interpretation: An epimer of D-fructose at
Concept introduction: Two compounds which are neither superimposable nor mirror images to each other and the configuration of one of their stereogenic centers is different are known as epimers.
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Organic Chemistry (6th Edition)
- For the single step reaction: A + B → 2C + 25 kJ If the activation energy for this reaction is 35.8 kJ, sketch an energy vs. reaction coordinate diagram for this reaction. Be sure to label the following on your diagram: each of the axes, reactant compounds and product compounds, enthalpy of reaction, activation energy of the forward reaction with the correct value, activation energy of the backwards reaction with the correct value and the transition state. In the same sketch you drew, after the addition of a homogeneous catalyst, show how it would change the graph. Label any new line "catalyst" and label any new activation energy.arrow_forwardHow many grams of C are combined with 3.75 ✕ 1023 atoms of H in the compound C5H12?arrow_forwarde. f. CH3O. יון Br NaOCH3 OCH 3 Br H₂Oarrow_forward
- Don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forward5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forward
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