EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 26, Problem 8RQ
Define (a) friability, (b) wear flat, (c) grinding ratio, (d) truing, and (e) dressing.
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Estimate the manufacturing cost for a simple machined component: a. Compare the costs for manufacturing volumes of 1, 10, 100, 1000, and 10,000 pieces with an intermediate tolerance and surface finish. Explain why there is a great change between 1 and 10 and a small change between 1000 and 10,000 pieces. b. Compare the costs for fit, intermediate, and rough tolerances with a volume of 100 pieces. c. Compare the costs of manufacturing the component out of various materials.
(Grinding Operations and Grinding Machines)
(USCS units) In a centerless grinding operation, the grinding wheel diameter = 8 in, and the regulating
wheel diameter = 5.0 in. The grinding wheel rotates at 1500 rev/min, and the regulating wheel rotates at
180 rev/min. The inclination angle of the regulating wheel = 2.3°º. Determine the production rate of
cylindrical work parts whose diameter = 0.5 in and length = 5.0 in.
Rod Mills, Ball Mills and Autogenous Mills are different types of tumbling mills used in the metalliferous industry. What equipment, if any, usually accompanies each of these mills in grinding circuits and why.
Chapter 26 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 26 - What is an abrasive? What are superabrasives?Ch. 26 - How is the size of an abrasive grain related to...Ch. 26 - Why are most abrasives made synthetically?Ch. 26 - Describe the structure of a grinding wheel and its...Ch. 26 - Explain the characteristics of each type of bond...Ch. 26 - What causes grinding sparks in grinding? Is it...Ch. 26 - Define metallurgical burn.Ch. 26 - Define (a) friability, (b) wear flat, (c) grinding...Ch. 26 - What is creep-feed grinding and what are its...Ch. 26 - How is centerless grinding different from...
Ch. 26 - What are the differences between coated and bonded...Ch. 26 - What is the purpose of the slurry in...Ch. 26 - Explain why grinding operations may be necessary...Ch. 26 - Why is there such a wide variety of types, shapes,...Ch. 26 - Prob. 15QLPCh. 26 - The grinding ratio, G, depends on the type of...Ch. 26 - What are the consequences of allowing the...Ch. 26 - Explain why speeds are much higher in grinding...Ch. 26 - Prob. 19QLPCh. 26 - Prob. 20QLPCh. 26 - Prob. 21QLPCh. 26 - Referring to the preceding chapters on processing...Ch. 26 - Explain the reasons that so many deburring...Ch. 26 - What precautions should you take when grinding...Ch. 26 - Prob. 25QLPCh. 26 - What factors could contribute to chatter in...Ch. 26 - Prob. 27QLPCh. 26 - Prob. 28QLPCh. 26 - Describe the effects of a wear flat on the overall...Ch. 26 - What difficulties, if any, could you encounter in...Ch. 26 - Prob. 31QLPCh. 26 - Prob. 32QLPCh. 26 - Prob. 33QLPCh. 26 - Jewelry applications require the grinding of...Ch. 26 - List and explain factors that contribute to poor...Ch. 26 - Calculate the chip dimensions in surface grinding...Ch. 26 - If the strength of the workpiece material is...Ch. 26 - Assume that a surface-grinding operation is being...Ch. 26 - Estimate the percent increase in the cost of the...Ch. 26 - Assume that the energy cost for grinding an...Ch. 26 - It is known that, in grinding, heat checking...Ch. 26 - Prob. 45QTPCh. 26 - With appropriate sketches, describe the principles...Ch. 26 - Prob. 47SDPCh. 26 - Vitrified grinding wheels (also called ceramic...Ch. 26 - Conduct a literature search, and explain how...Ch. 26 - Visit a large hardware store and inspect the...Ch. 26 - Obtain a small grinding wheel or a piece of a...Ch. 26 - In reviewing the abrasive machining processes in...Ch. 26 - Obtain pieces of sandpaper and emery cloth of...Ch. 26 - On the basis of the contents of this chapter,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Estimate the relative cost of grinding a steel part to a tolerance of ±0.0005 in versus turning it to a tolerance of +0.003 in.arrow_forwardmanufacturing technology please answer as soon as possiblearrow_forward(Grinding) (SI units) Wheel diameter = 160 mm, and infeed = 0.03 mm in a surface grinding operation. Wheel speed = 1500 m/min, work speed = 0.25 m/s, and crossfeed = 4 mm. The number of active grits per area of wheel surface = 35 grits/cm2. When the wheel is engaged in the work, determine: a. average length per chip, b. metal removal rate, and c. number of chips formed per unit time for the portion of the operationarrow_forward
- (Grinding) (SI units) Wheel diameter = 160 mm, and infeed = 0.03 mm in a surface grinding operation. Wheel speed = 1500 m/min, work speed = 0.25 m/s, and crossfeed = 4 mm. The number of active grits per area of wheel surface = 35 grits/cm². When the wheel is engaged in the work, determine: a. average length per chip, b. metal removal rate, and C. number of chips formed per unit time for the portion of the operation equations used; lc = √Dd RMR = vwwd U = Fev vwwdarrow_forward(a) Describe three basic categories of material removal process. (b) What is the different between machining with another manufacturing process. (c) Explain the advantages and disadvantages machining process. (d) Briefly explain the difference between roughing and finishing operation in machining.arrow_forwardWhy dressing is required for a continuously used wheel? and how can we dress a grinding wheel?arrow_forward
- Problem 5. (Grinding Operations and Grinding Machines) (USCS units) In a centerless grinding operation, the grinding wheel diameter = 8 in, and the regulating wheel diameter = 5.0 in. The grinding wheel rotates at 1500 rev/min, and the regulating wheel rotates at 180 rev/min. The inclination angle of the regulating wheel = 2.3°. Determine the production rate of cylindrical work parts whose diameter = 0.5 in and length = 5.0 in. Equations used V = TDN RMR lc = = √ Dd rg = vwwd nc = U w' vwC Fev Vwwd 0.25 w d K₁ (TWOW) 0.5 (1) 0² VC D F'c = K₁ Ts = K₂d0.75 GR= Vw Vg 0.5 (TCU) OD fr = TD,N, sin I D0.25arrow_forwardDear Tutor please help me pleasearrow_forward1) Identify what are the step by step machining and grinding processes to produce that part from a blank material. Assume that both part made from cast iron. 2) Then, taking into consideration of green manufacturing/ sustainability, you need to suggest what kind of improvement that you could do to the list of machining processes that you have identified (e.g. change of machining operation, use of dry machining instead of using cutting fluid or etc.) to reduce power consumption during machining, reduce waste and even pollution. Please give justification on your suggestions. 3). You need to include the figure of your chosen part and label the processes involve.arrow_forward
- 11) An internal bore is ground to 100 mm, removing 0.3 mm stock. To accomplish this, a grinding wheel 80% of the finished size is used. The wheel is dressed every 15 cycles because it is observed that the radial wheel wear is 0.05 mm on average. Assume wheel and part widths are equal. a. What dressing depth would you recommend and why? b. Calculate the G-ratio of this operation.arrow_forwardSpeed of Ball Mill In a ball mill of diameter 2000 mm, 100 mm dia steel balls are being used for grinding. Presently, for the material being ground, the mill is run at 15 rpm. At what speed will the mill have to be run if the 100 mm balls are replaced by 50 mm balls, all the other conditions remaining the same?arrow_forward6MENG201 Mechanical workshop practicearrow_forward
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