PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
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Chapter 26, Problem 72P
To determine

Show that: the magnitude force on each pole is given as qmB

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The magnetic force acting on a straight wire carrying current I of length L in a uniform magnetic field B is given by F = IL x B, where L has length L and is pointing in the direction of the current. Consider the loop centered at the origin shown in the figure below. y= 4-x* for -24x42 -2 2 (b) The torque with respect to a pivot point is defined by the cross product of the separation vector i which is oriented from the pivot point to the point where the force acts and the force, チ=チxF. Find the torque acting on this loop with respect to the origin as the pivot point.
The magnetic dipole moment of a current-carrying loop of wire is in the positive z direction. If a uniform magnetic field is in the positive x direction the magnetic torque on the loop is: (0 , in the positive y direction, in the negative y direction, in the positive z direction, in the negative z direction.)
The armature (slender rod) AB has a mass of 0.20 kg and can pivot about the pin at A. Movement is controlled by the electromagnet E, which exerts a horizontal attractive force on the armature at B of FB = (0.20 (10–3) l 2) N, Part A where l in meters is the gap between the armature and the magnet at any instant. (Figure 1) If the armature lies in the horizontal plane, and is originally at rest, determine the speed of the contact at B the instant l = 0.01 m. Originally l = 0.02 m. Express your answer to three significant figures and include the appropriate units. Value Units v = Submit Request Answer < Return to Assignment Provide Feedback Figure < 1 of 1 E 150 mm

Chapter 26 Solutions

PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS

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