PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
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Chapter 26, Problem 39P

(a)

To determine

The radius of curvature of ion’s orbit.

(b)

To determine

The difference in the orbital radii.

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Students have asked these similar questions
A negative charge, q = -7.2 nC follows a circular path due to the force caused by the magnetic field. If the magnetic field, B = 4.1 T causes charge to follow a radius of r = 3.2 µm, how fast (v = ?), in m/s, does the charge move? The mass of the charge is 5.56 x 10^-22 kg. Disregard any effects caused by special relativity.
For this question, we have to consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 T. What is the potential difference, in volts, required to accelerate electrons to a speed of 5.8 * 10^(7) ? Also what is the radius of curvature, in meters, of the path of a proton accelerated through this same potential after the proton crosses into the region with the magnetic field?  This is not a graded question
Q. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?

Chapter 26 Solutions

PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS

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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY