ORGANIC CHEMISTRY W/ALEKS
ORGANIC CHEMISTRY W/ALEKS
6th Edition
ISBN: 9781264905430
Author: SMITH
Publisher: MCG CUSTOM
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Chapter 26, Problem 40P
Interpretation Introduction

(a)

Interpretation: The enantiomer of D-arabinose is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(b)

Interpretation: An epimer of D-arabinose at C3 is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(c)

Interpretation: The diastereomer that is not an epimer of D-arabinose is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(d)

Interpretation: The constitutional isomer of D-arabinose contains a carbonyl group is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

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Students have asked these similar questions
For D-arabinose:a. Draw its enantiomer.b. Draw an epimer at C3.c. Draw a diastereomer that is not an epimer.d. Draw a constitutional isomer that still contains a carbonyl group.
Can you help me to solve this?
a. How many stereogenic centers are present in α-D-galactose? b. Label the hemiacetal carbon in α-D-galactose. c. Draw the structure of β-D-galactose. d. Draw the structure of the polyhydroxy aldehyde that cyclizes to α- and β-D-galactose.

Chapter 26 Solutions

ORGANIC CHEMISTRY W/ALEKS

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