A certain diet pill is designed to delay the administration of the active ingredient for several hours. The concentration C t (in mg/L) of the active ingredient in the bloodstream t hours after taking the pill is modeled by C t = 3 t 2 t 2 + 20 t + 51 a. Use a graphics utility to graph the function. b. What are the domain restrictions on the function? c Use the graph to approximate the maximum concentration. Round to the nearest mg/L. d. What is the limiting concentration?
A certain diet pill is designed to delay the administration of the active ingredient for several hours. The concentration C t (in mg/L) of the active ingredient in the bloodstream t hours after taking the pill is modeled by C t = 3 t 2 t 2 + 20 t + 51 a. Use a graphics utility to graph the function. b. What are the domain restrictions on the function? c Use the graph to approximate the maximum concentration. Round to the nearest mg/L. d. What is the limiting concentration?
Solution Summary: The graph of the function is shown below. The curve in the graph shows the turning point x=5
A certain diet pill is designed to delay the administration of the active ingredient for several hours. The concentration
C
t
(in mg/L) of the active ingredient in the bloodstream t hours after taking the pill is modeled by
C
t
=
3
t
2
t
2
+
20
t
+
51
a. Use a graphics utility to graph the function.
b. What are the domain restrictions on the function?
c Use the graph to approximate the maximum concentration. Round to the nearest mg/L.
Write the given third order linear equation as an equivalent system of first order equations with initial values.
Use
Y1 = Y, Y2 = y', and y3 = y".
-
-
√ (3t¹ + 3 − t³)y" — y" + (3t² + 3)y' + (3t — 3t¹) y = 1 − 3t²
\y(3) = 1, y′(3) = −2, y″(3) = −3
(8) - (888) -
with initial values
Y
=
If you don't get this in 3 tries, you can get a hint.
Question 2
1 pts
Let A be the value of the triple integral
SSS.
(x³ y² z) dV where D is the region
D
bounded by the planes 3z + 5y = 15, 4z — 5y = 20, x = 0, x = 1, and z = 0.
Then the value of sin(3A) is
-0.003
0.496
-0.408
-0.420
0.384
-0.162
0.367
0.364
Question 1
Let A be the value of the triple integral SSS₂ (x + 22)
=
1 pts
dV where D is the
region in
0, y = 2, y = 2x, z = 0, and
the first octant bounded by the planes x
z = 1 + 2x + y. Then the value of cos(A/4) is
-0.411
0.709
0.067
-0.841
0.578
-0.913
-0.908
-0.120
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