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- 7) A wire with 4 meters length and constant charge density lambda = 4nC/m is placed diagonally on x-y plane. One end is at the origin and it makes 45 degrees with the x-axis. Find the integral expression for Ex at x=7 y=10arrow_forward(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 8.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol. 236000000000 X You can approach this problem as a unit conversion exercise in that you need to convert grams of silver to electrons using the information given in the problem as conversion factors (b) Imagine adding electrons to the pin until the negative charge has the very large value 1.00 mC. How many electrons are added for every 109 electrons already present? X 5.30 Note that 109 is one billion. It might help to rewrite your answer from part (a) as the number of billions of electrons. Need Help? Read It Watch Itarrow_forwardB5arrow_forward
- (1 )Region one z>0 consist of dielectric medium (er=4) (2)Region two z<0 consist of perfect conductor. Determine D&E at point (3,2,-3) and point (2,-1,3), if the surface charge on the conductor is equal to 8nc/m?arrow_forwardA spherical metallic object with a hole inside initially holds a net charge of 94.9 nC; the hole is initially charge-free. Then a particle with a charge of 26.1 nC is placed at the center of the hole (held by a perfect non-polarizable insulating material). The value of the net charge on the outer surface of the conductor, upon reaching electrostatic equilibrium, is most nearly (A) –68.8 nC. (B) –121 nC. (C) 68.8 nC. (D) 42.7 nC. (E) 121 nC.arrow_forward35 SSM In crystals of the salt cesium chloride, cesium ions Cs+ form the eight corners of a cube and a chlorine ion Cl is at the cube's center (Fig. 21-36). The edge length of the cube is 0.40 nm. The Cst ions are each deficient by one electron (and thus each has a charge of +e), and the Cl- ion has one excess electron (and thus has a charge of -e). (a) What is the magnitude of the net electro- static force exerted on the Cl ion by the eight Cs ions at the cor- ners of the cube? (b) If one of the Cs* ions is missing, the crystal is said to have a defect; what is the magnitude of the net electrostatic force exerted on the Cl- ion by the seven remaining Cs+ ions? Cs+ 0.40 nmarrow_forward
- Two parallel conducting plates are seperated by 1.0 mm and carry equal but opposite charge densities. If the difference between them is 2.0 V, what is the magnitude of the surface charge density on each plate?arrow_forwardPoint charges Q are distributed throughout an infinite slab of width W located over –arrow_forward(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 13.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol. (b) Imagine adding electrons to the pin until the negative charge has the very large value 1.00 mC. How many electrons are added for every 109 electrons already present?arrow_forwardProblem 4) A large dielectric plate of thickness a is lying in the x-y plane. The charge density of the conductor varies along the z position according to the following equation: p(z) = Po(1 + z?) for -arrow_forward*39 SSM In Fig. 23-49, a small, nonconducting ball of mass m = 1.0 mg and charge q = 2.0 x 10-8C (distributed uniformly through its vol- ume) hangs from an insulating thread that makes an angle 0 = 30° with a vertical, uniformly charged nonconducting sheet (shown in cross sec- tion). Considering the gravitational force on the ball and assuming the sheet extends far vertically and into and out of the page, calculate the surface charge density o of the sheet. m.arrow_forwardThe surfaces of a lipid bi-layer forming the membrane around a cell with a radius of 1.2 µm has a residual charge qr = 9x10-15 C on outside of the bi-layer, and the same amount of negative charge on the inside. What is the force in pN (×10-12 N) on a singly-charged positive ion (q =1.6 x10-19 C) located on the outer surface of this membrane? Hint: Use F = q E = q (o/e) with o = qr/A = qr/ (4Tt r²) and ɛ, = 8.85 x 10-12 F-m-1. Answer: 8.99180 Farrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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