Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
Question
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Chapter 25, Problem 34PS

(a)

Interpretation Introduction

Interpretation:

An equation for the decomposition of Iodine-131 has to be written.

Concept introduction:

Balancing nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number.

  • The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction.
  • The sum of atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.

 (b)

Interpretation Introduction

Interpretation:

The time required for the activity of Idodine-131 to decrease to 35% of its original value has to be calculated.

Concept Introduction:

Radiocarbon dating: The dynamic equilibrium exists in all living organism by exhaling or inhaling, maintain the same ratio of 12C and 14C that takes in. when the living organism dies, the intake of 14C stops and it’s the ratio no longer exhibits equilibrium; undergoes radioactive decay.

Half-life period: The time required to reduce to half of its initial value.

Formula used to calculate half-life:

t1/2=0.693kwhere,kis rate constant.(or)ln[N]t- ln[N]0= -kt

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The initial rates method can be used to determine the rate law for a reaction. using the data for the reaction below, what is the rate law for reaction? A+B-C - ALA] At (mot Trial [A] (mol) (MD 2 1 0.075 [B]( 0.075 mo LS 01350 2 0.075 0.090 0.1944 3 0.090 0.075 0.1350 Report value of k with two significant Figure
Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0m
Can you please explain this problem to me and expand it so I can understand the full Lewis dot structure? Thanks!

Chapter 25 Solutions

Chemistry & Chemical Reactivity

Ch. 25.4 - Prob. 3CYUCh. 25.4 - Prob. 1RCCh. 25.4 - Prob. 2RCCh. 25.5 - Prob. 1CYUCh. 25.5 - Prob. 1RCCh. 25.6 - Prob. 1RCCh. 25.9 - Prob. 1CYUCh. 25.9 - Prob. 1QCh. 25.9 - Prob. 2QCh. 25.9 - Prob. 3QCh. 25.9 - Prob. 4QCh. 25.9 - Prob. 5QCh. 25.9 - Prob. 6QCh. 25.A - Prob. 1QCh. 25.A - Prob. 2QCh. 25.A - Prob. 3QCh. 25.A - Prob. 4QCh. 25 - Prob. 1PSCh. 25 - Prob. 4PSCh. 25 - Prob. 5PSCh. 25 - Prob. 6PSCh. 25 - Prob. 7PSCh. 25 - Prob. 8PSCh. 25 - Prob. 9PSCh. 25 - Prob. 11PSCh. 25 - Prob. 12PSCh. 25 - Prob. 13PSCh. 25 - Prob. 14PSCh. 25 - Prob. 15PSCh. 25 - Prob. 16PSCh. 25 - Prob. 17PSCh. 25 - Prob. 18PSCh. 25 - Prob. 19PSCh. 25 - Prob. 20PSCh. 25 - Prob. 21PSCh. 25 - Prob. 22PSCh. 25 - Prob. 23PSCh. 25 - Prob. 24PSCh. 25 - Prob. 25PSCh. 25 - Prob. 26PSCh. 25 - Prob. 27PSCh. 25 - Prob. 28PSCh. 25 - Prob. 29PSCh. 25 - Prob. 30PSCh. 25 - Prob. 31PSCh. 25 - Prob. 32PSCh. 25 - Prob. 33PSCh. 25 - Prob. 34PSCh. 25 - Prob. 35PSCh. 25 - Prob. 36PSCh. 25 - Prob. 37PSCh. 25 - Prob. 38PSCh. 25 - Prob. 39PSCh. 25 - Prob. 40PSCh. 25 - Prob. 41PSCh. 25 - Prob. 42PSCh. 25 - Prob. 43PSCh. 25 - Prob. 44PSCh. 25 - Prob. 45PSCh. 25 - Some of the reactions explored by Ernest...Ch. 25 - Prob. 47GQCh. 25 - Prob. 48GQCh. 25 - Prob. 49GQCh. 25 - Prob. 50GQCh. 25 - Prob. 51GQCh. 25 - Prob. 52GQCh. 25 - Prob. 53GQCh. 25 - Prob. 54GQCh. 25 - Prob. 55ILCh. 25 - Prob. 56ILCh. 25 - Prob. 57ILCh. 25 - Prob. 58ILCh. 25 - Prob. 59ILCh. 25 - Prob. 60ILCh. 25 - Prob. 61SCQCh. 25 - Prob. 62SCQCh. 25 - Prob. 63SCQCh. 25 - Prob. 64SCQCh. 25 - Prob. 66SCQCh. 25 - Prob. 67SCQCh. 25 - Prob. 68SCQCh. 25 - Prob. 69SCQ
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