Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Edition; Modified Mastering Chemistry with Pearson eText -- ValuePack ... and Biological Chemistry (4th Edition)
4th Edition
ISBN: 9780134465715
Author: John E. McMurry, David S. Ballantine
Publisher: PEARSON
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Chapter 25, Problem 25.47CP
Interpretation Introduction
Interpretation:
Based on the metabolic processes, the biochemistry of the body is dynamic has to be explained.
Concept introduction:
- Entire collection of free amino acids throughout the body is called amino acid pool.
- All tissues and
biomolecules in the body are constantly being degraded, repaired and replaced through a process known as turnover. - The citric acid cycle includes a series of
oxidation-reduction reactions in mitochondria that results in the oxidation of an acetyl group to two molecules of carbon dioxide and reduce the coenzymes that are reoxidized through the electron transport chain, linked to the formation of ATP - Urea cycle is the cyclic biochemical pathway that produces urea for excretion.
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The preferred substrate is T because the enzyme half-saturates at 7.00 mM for T, but requires 28.0 mM for U, and 112 mM for S.
b
Question Content Area
The rate constant k 2 with substrate S is 9.60×107 sec-1, with substrate T, k 2 = 6.00×104 sec-1, and with substrate U, k 2 = 2.40×106 sec-1.
Calculate the catalytic efficiency with S, T, and U.
Catalytic efficiency with S =
Catalytic efficiency with T =
Catalytic efficiency with U =
Does enzyme A use substrate S, substrate T, or substrate U with greater catalytic efficiency?
Fumerase catalyzes the conversion of fumerate to malate.
fumerate + H2O ⇋ malate
The turnover number, kcat, for fumerase is 8.00×102 sec-1. The Km of this enzyme for fumerate is 5.00×10-3 μmol mL-1.
a
In an experiment using 2.00×10-3 μmol·mL-1, what is Vmax?
Suppose you wanted to make a buffer of exactly pH 7.00 using KH2PO4 and Na2HPO4. If the final solution was 0.18 M in KH2PO4, you would need 0.25 M Na2HPO4. Now assume you wish to make a buffer at the same pH, using the same substances, but want the total phosphate molarity ([HPO42−]+[H2PO−4]) to equal 0.20 M. What concentration of the Na2HPO4 would be required?
Chapter 25 Solutions
Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Edition; Modified Mastering Chemistry with Pearson eText -- ValuePack ... and Biological Chemistry (4th Edition)
Ch. 25.2 - Prob. 25.1PCh. 25.2 - Prob. 25.2KCPCh. 25.3 - Prob. 25.3PCh. 25.3 - Prob. 25.4PCh. 25.3 - Prob. 25.5PCh. 25.3 - Prob. 25.6PCh. 25.4 - Prob. 25.1CIAPCh. 25.4 - Prob. 25.2CIAPCh. 25.4 - Prob. 25.3CIAPCh. 25.4 - Prob. 25.7P
Ch. 25.4 - Prob. 25.8KCPCh. 25.6 - Prob. 25.9PCh. 25.6 - Prob. 25.10KCPCh. 25.6 - What is meant by a conditional amino acid?Ch. 25.6 - Prob. 25.5CIAPCh. 25.6 - Prob. 25.6CIAPCh. 25 - In the diagram shown here, fill in the sources for...Ch. 25 - Prob. 25.12UKCCh. 25 - Prob. 25.13UKCCh. 25 - Prob. 25.14UKCCh. 25 - Prob. 25.15UKCCh. 25 - Prob. 25.16UKCCh. 25 - Prob. 25.17APCh. 25 - Prob. 25.18APCh. 25 - Prob. 25.19APCh. 25 - Prob. 25.20APCh. 25 - Prob. 25.21APCh. 25 - Prob. 25.22APCh. 25 - What is the structure of the -keto acid formed...Ch. 25 - Prob. 25.24APCh. 25 - In general, how does oxidative deamination differ...Ch. 25 - Prob. 25.26APCh. 25 - Prob. 25.27APCh. 25 - Prob. 25.28APCh. 25 - Prob. 25.29APCh. 25 - Prob. 25.30APCh. 25 - Prob. 25.31APCh. 25 - Prob. 25.32APCh. 25 - Prob. 25.33APCh. 25 - Prob. 25.34APCh. 25 - How do essential and nonessential amino acids...Ch. 25 - Prob. 25.36APCh. 25 - Prob. 25.37APCh. 25 - How is tyrosine biosynthesized in the body? What...Ch. 25 - Prob. 25.39APCh. 25 - Prob. 25.40APCh. 25 - Prob. 25.41APCh. 25 - What energy source is used in the formation of...Ch. 25 - Write the equation for the transamination reaction...Ch. 25 - Prob. 25.44CPCh. 25 - Prob. 25.45CPCh. 25 - Prob. 25.46CPCh. 25 - Prob. 25.47CPCh. 25 - Prob. 25.48CPCh. 25 - Prob. 25.49CPCh. 25 - Prob. 25.50CPCh. 25 - Prob. 25.51CPCh. 25 - Prob. 25.52CPCh. 25 - Why might it be a bad idea to take large...Ch. 25 - Prob. 25.54GPCh. 25 - Prob. 25.55GPCh. 25 - Prob. 25.56GP
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