The monosaccharide units present in raffinose has to be named.

Question

Relative Intensity Part VI. consider the multi-step reaction below for compounds A, B, and C. These compounds were subjected to mass spectrometric analysis and the following spectra for A, B, and C was obtained. Draw the structure of B and C and match all three compounds to the correct spectra. Relative Intensity Relative Intensity 100 HS-NJ-0547 80 60 31 20 S1 84 M+ absent 10 30 40 50 60 70 80 90 100 100- MS2016-05353CM 80- 60 40 20 135 137 S2 164 166 0-m 25 50 75 100 125 150 m/z 60 100 MS-NJ-09-43 40 20 20 80 45 S3 25 50 75 100 125 150 175 m/z

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

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Relative Intensity Part VI. consider the multi-step reaction below for compounds A, B, and C. These compounds were subjected to mass spectrometric analysis and the following spectra for A, B, and C was obtained. Draw the structure of B and C and match all three compounds to the correct spectra. Relative Intensity Relative Intensity 100 HS-NJ-0547 80 60 31 20 S1 84 M+ absent 10 30 40 50 60 70 80 90 100 100- MS2016-05353CM 80- 60 40 20 135 137 S2 164 166 0-m 25 50 75 100 125 150 m/z 60 100 MS-NJ-09-43 40 20 20 80 45 S3 25 50 75 100 125 150 175 m/z

Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100

Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Expert Solution & Answer

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Expert Solution & Answer

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

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Answer 5

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Answer 6

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

Answer 7

Chapter 25, Problem 25.37P

(a)

Interpretation Introduction

Interpretation:

The monosaccharide units present in raffinose has to be named.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

Answer 11

(c)

Interpretation Introduction

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

Answer 12

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Answer 13

(d)

Interpretation Introduction

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Answer 14

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Answer 25

Ch. 25.1 - Prob. 25.1P Ch. 25.2 - Prob. 25.2P Ch. 25.2 - Prob. 25.3P Ch. 25.3 - Prob. 25.4P Ch. 25.3 - Prob. 25.5P Ch. 25.3 - Prob. AQ Ch. 25.3 - Prob. BQ Ch. 25.3 - Prob. CQ Ch. 25.3 - Prob. DQ Ch. 25.3 - How many stereoisomers would result from the...

The monosaccharide units present in raffinose has to be named.

Concept explainers

Interpretation:

The monosaccharide units present in raffinose has to be named.

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Chapter 25 Solutions

The monosaccharide units present in raffinose has to be named.

Concept explainers

Interpretation: The monosaccharide units present in raffinose has to be named.

Interpretation: The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

Interpretation: Raffinose is a reducing sugar or not has to be stated. Concept-Introduction: Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

Interpretation: Raffinose reacts with how many moles of periodic acid has to be given. Concept Introduction: The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.

Chapter 25 Solutions

Interpretation:

The monosaccharide units present in raffinose has to be named.

Interpretation:

The glycosidic bonds formed by the linkage of three monomers to form the trisaccharide has to be given.

Interpretation:

Raffinose is a reducing sugar or not has to be stated.

Concept-Introduction:

Reducing sugars are the carbohydrates which contains free carbonyl groups (aldehyde or ketone group). They are oxidized by the oxidizing agents by reducing the oxidizing agent.

Interpretation:

Raffinose reacts with how many moles of periodic acid has to be given.

Concept Introduction:

The periodic acid cleaves carbon-carbon bonds with α-hydroxyketones and α-hydroxyaldehydes. In carbohydrates, the reaction is useful for the determination of structure.