AVC LOOSELEAF CHEMISTRY W/CONNECT 2 SEM
13th Edition
ISBN: 9781260987164
Author: Chang
Publisher: MCG CUSTOM
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Chapter 25, Problem 25.30QP
Interpretation Introduction
Interpretation:
The given two sample which one is higher melting point has to be identified.
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When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment?
a) the heat capacity of the calorimeter
b) Mass of sample
c) Ti
d) The molarity of the HCl
e) Tf
Predict products for the Following organic rxn/s by
writing the structurels of the correct products. Write
above the line provided"
your answer
D2
①CH3(CH2) 5 CH3 + D₂ (adequate)"
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2
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Spark
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4 CH 3 11
3 CH 3 (CH2) 4 C-H + CH3OH
CH2 CH3 + CH3 CH2OH
0
CH3
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KMnDy→
C43
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C-OH
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1110
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9+3
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0
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+ CH3 C-OH + Heat
CH2CH3
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2
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CH 3 CH₂ CH₂ C = CH + 2 H₂ →
2
2
Chapter 25 Solutions
AVC LOOSELEAF CHEMISTRY W/CONNECT 2 SEM
Ch. 25 - Prob. 25.1QPCh. 25 - Prob. 25.2QPCh. 25 - Prob. 25.3QPCh. 25 - Prob. 25.4QPCh. 25 - Prob. 25.5QPCh. 25 - Prob. 25.6QPCh. 25 - Prob. 25.7QPCh. 25 - Prob. 25.8QPCh. 25 - Prob. 25.9QPCh. 25 - Prob. 25.10QP
Ch. 25 - Prob. 25.11QPCh. 25 - Prob. 25.12QPCh. 25 - Prob. 25.13QPCh. 25 - Prob. 25.14QPCh. 25 - Prob. 25.15QPCh. 25 - Prob. 25.16QPCh. 25 - Prob. 25.17QPCh. 25 - Prob. 25.18QPCh. 25 - Prob. 25.19QPCh. 25 - Prob. 25.20QPCh. 25 - Prob. 25.21QPCh. 25 - Prob. 25.22QPCh. 25 - Prob. 25.23QPCh. 25 - Prob. 25.24QPCh. 25 - Prob. 25.25QPCh. 25 - Prob. 25.26QPCh. 25 - Discuss the importance of hydrogen bonding in...Ch. 25 - Proteins vary widely in structure, whereas nucleic...Ch. 25 - Prob. 25.29QPCh. 25 - Prob. 25.30QPCh. 25 - Prob. 25.31QPCh. 25 - Prob. 25.32QPCh. 25 - Prob. 25.33QPCh. 25 - Prob. 25.34QPCh. 25 - Prob. 25.35QPCh. 25 - Chemical analysis shows that hemoglobin contains...Ch. 25 - Prob. 25.37QPCh. 25 - What kind of intermolecular forces are responsible...Ch. 25 - Draw structures of the nucleotides containing the...Ch. 25 - Prob. 25.40QPCh. 25 - Prob. 25.41QPCh. 25 - Prob. 25.42QPCh. 25 - Prob. 25.43QPCh. 25 - Prob. 25.44QPCh. 25 - When deoxyhemoglobin crystals are exposed to...Ch. 25 - Prob. 25.46QPCh. 25 - Prob. 25.47QPCh. 25 - Prob. 25.48QPCh. 25 - Prob. 25.49QPCh. 25 - Prob. 25.50QPCh. 25 - Prob. 25.51QPCh. 25 - Assume the energy of hydrogen bonds per base pair...Ch. 25 - Prob. 25.53QP
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- potential energy Br b) Translate the Newman projection below to its wedge-and-dash drawing. F H. OH CH3 CI c) Isopentane (2-methylbutane) is a compound containing a branched carbon chain. Draw a Newman projection of six conformations about the C2-C3 bond of isopentane. On the curve of potential energy versus angle of internal rotation for isopentane, label each energy maximum and minimum with one of the conformations. 0° 。 F A B D C angle of internal rotation E F 360° (=0°) JDownlarrow_forwardQ7: Identify the functional groups in these molecules a) CH 3 b) Aspirin: HO 'N' Capsaicin HO O CH3 CH 3arrow_forwardQ2: Name the following alkanesarrow_forward
- 1. Complete the following table in your laboratory notebook. Substance Formula Methanol CH3OH Ethanol C2H5OH 1-Propanol C3H7OH 1-Butanol C4H9OH Pentane C5H12 Hexane C6H14 Water H₂O Acetone C3H60 Structural Formula Molecular Weight (g/mol) Hydrogen Bond (Yes or No)arrow_forwardQ1: Compare the relative acidity in each pair of compounds. Briefly explain. (a) CH3OH vs NH 3 (b) HF vs CH3COOH (c) NH3 vs CH4 (d) HCI vs HI (e) CH3COOH vs CH3SH (f) H₂C=CH2 vs CH3 CH3 (g) compare the acidity of the two bolded hydrogens O. H N- (h) compare the acidity of the two bolded hydrogens, draw resonance structures to explain H H Harrow_forwardQ3: Rank the following molecules in order of decreasing boiling point: (a) 3-methylheptane; (b) octane; (c) 2,4-dimethylhexane; (d) 2,2,4-trimethylpentane.arrow_forward
- Q5: Conformations of Alkanes a) Draw a Newman Projection of the compound below about the C2-C3 bond. H3C Cli... H IIIH Br CH3arrow_forwardThe ability of atoms to associate with each other depends ona) the electronic structure and its spatial orientation.b) the electron affinity.c) The other two answers are correct.arrow_forwardWhat is the final volume after you reach the final temperature? I put 1.73 but the answer is wrong not sure why The initial volume of gas is 1.60 LL , the initial temperature of the gas is 23.0 °C°C , and the system is in equilibrium with an external pressure of 1.2 bar (given by the sum of a 1 bar atmospheric pressure and a 0.2 bar pressure due to a brick that rests on top of the piston). Then, as you did in Exercise 1, you heat the gas slowly until the temperature reaches 48.2 °Carrow_forward
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