Universe
Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 25, Problem 17Q
To determine

The reason due to which astronmers conisder the Hubble constant as the “Hubble variable”.

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23.4 g of coffee beans at room temperature (18.6 °C) is mixed into 316 g of water at 96.8 °C in an effort to make coffee. The entire system is poured in a 363 g ceramic mug. Assume the mug is initally also at room temperature (18.6 °C). What is the final temperature of the mixture? The specific heat of ground coffee beans is 1670 J/kg˚C, the specific heat of water is 4186 J/kg˚C, and the specific heat of the mug is 850. J/kg˚C.
Snoop Dogg, in an effort to get laid back (with his mind on his money and his money on his mind) pours himself a gin and juice.  He mixes 0.124 kg (about 3 shots) of gin with 0.576 kg (about a pint) of orange juice. The gin starts at 20.0˚C, room temperature. The juice is refrigerated and starts at 2.89 ˚C. What is the final temperature after mixing of the gin and juice? The specific heat of gin is 3460 J/kg˚C and the specific heat of orange juice is 3730 J/kg˚C.
A sword is heated up to 226 °C, it is put into a nearby barrel of water that is at 18.4 °C.  What mass of water would be needed to cool the sword to 30.0˚C, bringing the system to thermal equilibrium?  The sword is 35.4 kg and is made of steel. The specific heat of water is = 4186 J/kg ˚C. The specific heat of steel is = 502 J/kg ˚C
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