The reason due to which the radiation temperature was T 0 = T ( 1 + z ) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ 0 from the cosmic microwave background was emitted at redshift z . Today it’s wavelength is, λ = λ 0 ( 1 + z ) .

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Answer 1

Question

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

Answer 2

Question

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

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Answer 3

Question

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

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Answer 4

Question

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

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Answer 5

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 6

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 7

Chapter 25, Problem 35Q

(a)

To determine

The reason due to which the radiation temperature was T0=T(1+z) at the redshift z. Let, T denotes today’s temperature of the cosmic microwave background. It is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 8

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 9

(b)

To determine

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 10

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 11

(c)

To determine

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 25 - Prob. 1CC Ch. 25 - Prob. 2CC Ch. 25 - Prob. 3CC Ch. 25 - Prob. 4CC Ch. 25 - Prob. 5CC Ch. 25 - Prob. 6CC Ch. 25 - Prob. 7CC Ch. 25 - Prob. 8CC Ch. 25 - Prob. 9CC Ch. 25 - Prob. 10CC

Solution Summary: The radiation temperature at the redshift z varies by a factor of (1+z), and the wavelength of the maximum emission is in inverse proportion to its temperature.

Concept explainers

The radiation temperature at z=1, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

The redshift at which the radiation temperature is equal to 293 K, if it is given that a proton of wavelength λ0 from the cosmic microwave background was emitted at redshift z. Today it’s wavelength is, λ=λ0(1+z).

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Chapter 25 Solutions