
Organic Chemistry
3rd Edition
ISBN: 9781119316152
Author: Klein, David R.
Publisher: WILEY
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Question
Chapter 24.7, Problem 39PTS
(a)
Interpretation Introduction
Interpretation:
The each given disaccharides are to be identified whether it is reducing sugar or not.
Concept introduction:
For the carbohydrates,
- Anomeric position is carried by an OH group for Hemiacetals.
- Anomeric position is carried by an alkoxy group for acetals.
- Hemiacetal sugars are in equilibrium with their open chain form.
- Acetal sugars are not in equilibrium with their open chain form.
- Reducing sugar: Sugars that contain
aldehyde or a freeketone groups that are oxidized tocarboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.
To identify: the given compound (a) is a reducing sugar or not.
(b)
Interpretation Introduction
Interpretation:
The each given disaccharides are to be identified whether it is reducing sugar or not.
Concept introduction:
For the carbohydrates,
- Anomeric position is carried by an OH group for Hemiacetals.
- Anomeric position is carried by an alkoxy group for acetals.
- Hemiacetal sugars are in equilibrium with their open chain form.
- Acetal sugars are not in equilibrium with their open chain form.
- Reducing sugar: Sugars that contain aldehyde or a free ketone groups that are oxidized to carboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.
(c)
Interpretation Introduction
Interpretation:
The each given disaccharides are to be identified whether it is reducing sugar or not.
Concept introduction:
For the carbohydrates,
- Anomeric position is carried by an OH group for Hemiacetals.
- Anomeric position is carried by an alkoxy group for acetals.
- Hemiacetal sugars are in equilibrium with their open chain form.
- Acetal sugars are not in equilibrium with their open chain form.
- Reducing sugar: Sugars that contain aldehyde or a free ketone groups that are oxidized to carboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.
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Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
е.
Д
CH3
D*, D20
C.
NaOMe,
Br
Br
Chapter 24 Solutions
Organic Chemistry
Ch. 24.2 - Prob. 1CCCh. 24.2 - Prob. 2CCCh. 24.2 - Prob. 3CCCh. 24.2 - Prob. 4CCCh. 24.2 - Prob. 5CCCh. 24.2 - Prob. 6CCCh. 24.4 - Prob. 7CCCh. 24.4 - Prob. 8CCCh. 24.5 - Prob. 1LTSCh. 24.5 - Prob. 9PTS
Ch. 24.5 - Prob. 10ATSCh. 24.5 - Prob. 11ATSCh. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12PTSCh. 24.5 - Prob. 13PTSCh. 24.5 - Prob. 14ATSCh. 24.5 - Prob. 15ATSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 17ATSCh. 24.5 - Prob. 18ATSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 32ATSCh. 24.6 - Prob. 33ATSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 40ATSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 81IPCh. 24 - Prob. 82IPCh. 24 - Prob. 83IPCh. 24 - Prob. 84IPCh. 24 - Prob. 85IPCh. 24 - Prob. 86IPCh. 24 - Prob. 87CPCh. 24 - Prob. 88CPCh. 24 - Prob. 89CP
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